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dybincka [34]
3 years ago
14

What is the exponent on 10 when you right 5.3 in scientific notation?

Mathematics
1 answer:
salantis [7]3 years ago
8 0
It is zero

the answer is 5.3 x 10^0
because 10^1 would force you to move the decimal place to make it 53

I hope this helps!
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Solve the system of linear equations.
sweet-ann [11.9K]

Answer:

  • dependent system
  • x = 2 -a
  • y = 1 +a
  • z = a

Step-by-step explanation:

Let's solve this by eliminating z, then we'll go from there.

Add 6 times the second equation to the first.

  (3x -3y +6z) +6(x +2y -z) = (3) +6(4)

  9x +9y = 27 . . . simplify

  x + y = 3 . . . . . . divide by 9 [eq4]

Add 13 times the second equation to the third.

  (5x -8y +13z) +13(x +2y -z) = (2) +13(4)

  18x +18y = 54

  x + y = 3 . . . . . . divide by 18 [eq5]

Equations [eq4] and [eq5] are identical. This tells us the system is dependent, and has an infinite number of solutions. We can find them in terms of z:

  y = 3 -x . . . . solve eq5 for y

  x +2(3 -x) -z = 4 . . . . substitute into the second equation

  -x +6 -z = 4

  x = 2 - z . . . . . . add x-4

  y = 3 -(2 -z)

  y = z +1

So far, we have written the solutions in terms of z. If we use the parameter "a", we can write the solutions as ...

  x = 2 -a

  y = 1 +a

  z = a

_____

<em>Check</em>

First equation:

  3(2-a) -3(a+1) +6a = 3

  6 -3a -3a -3 +6a = 3 . . . true

Second equation:

  (2-a) +2(a+1) -a = 4

  2 -a +2a +2 -a = 4 . . . true

Third equation:

  5(2-a) -8(a+1) +13a = 2

  10 -5a -8a -8 +13a = 2 . . . true

Our solution checks algebraically.

6 0
3 years ago
What is the percent difference between 3x to x
allsm [11]

Answer:

.03%

Step-by-step explanation:

6 0
2 years ago
Jacques wants to make up packs of $0.45 comic books mixed with $0.75 ones to sell at $9.00 per pack. The number of $0.45 comic b
Anna007 [38]

Answer:

The number of each type in the pack is 5 of $0.45 comic books and 9 of $0.75 comic books

Step-by-step explanation:

A system of linear equations is a set of two or more equations of the first degree, in which two or more unknowns are related.

Solving a system of equations consists of finding the value of each unknown so that all the equations of the system are satisfied.

In this case, the unknowns or unknown variables are:

x: number of $ 0.45 comic books

y: number of $ 0.75 comic books

Jacques wants to make up packs of $0.45 comic books mixed with $0.75 ones to sell at $9.00 per pack.  Then the equation that represents this situation is:

x*0.45 + y*0.75= 9

On the other side, the number of $0.45 comic books is 4 more than the number of $0.75 comic books.  Then the equation that represents this situation is:

x+4=y

The system of equations to solve is:

\left \{ {{x*0.45+y*0.75=9} \atop {x+4=y}} \right.

One way to solve a system of equations is the substitution method, which consists of solving one of the unknowns in one of the equations and substituting its value in the next.

In this case we directly replace the expression of the variable and of the second equation in the first:

x*0.45 + (x+4)*0.75= 9

Solving:

x*0.45 + 0.75*x + 4*0.75= 9

1.2*x + 3=9

1.2*x= 9-3

1.2*x= 6

x= 6÷ 1.2

x=5

Replacing this value in the expression x+4=y you get:

5 +4=y

9=y

<u><em>The number of each type in the pack is 5 of $0.45 comic books and 9 of $0.75 comic books</em></u>

8 0
3 years ago
Sum of rational Expression 9/xy + x^2/y
Ksenya-84 [330]
9/xy + x^2/y =  (9+x^3)/xy
4 0
3 years ago
Given sintheta =7/11 and sectheta is less than 0, find costheta and tantheta
Korvikt [17]

Answer:

Step-by-step explanation:

Sin theta is the ratio of side opposite over hypotenuse of a reference angle situated at the origin in an x-y coordinate plane.  If sec theta is negative, then the only quadrant where sin is positive AND sec is negative is quadrant 2.  Remember that sec theta is the inverse of cos theta.  Puttling our right triangle in QII, the side measuring 7 is across from the angle and the hypotenuse is 11.  In order to find the cos theta and tan theta, we need the side adjacent to the angle.  Use Pythagorean's Theorem to find the side adjacent.

11^2=7^2+x^2 and

121=47+x^2 and

72=x^2 so

x=6\sqrt{2}

Remember that this value is why the sec is negative.  Because x is negative in QII, the cos theta is side adjacent over hypotenuse:

cos\theta=-\frac{6\sqrt{2} }{11}  and

tan\theta=-\frac{7}{6\sqrt{2} }

But we should probably rationalize that denominator, so

tan\theta=-\frac{7}{6\sqrt{2} }*\frac{\sqrt{2} }{\sqrt{2} } =-\frac{7\sqrt{2} }{12}

5 0
3 years ago
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