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Alja [10]
3 years ago
7

3/2+2x/5=7/10 these are fraction busters but I don't know what I'm supposed to do and what the answer is?

Mathematics
1 answer:
MAXImum [283]3 years ago
3 0
<span>3/2+2x/5=7/10

We simplify the equation to the form, which is simple to understand
<span>3/2+2x/5=7/10

Simplifying:
<span>+1.5+2x/5=7/10

Simplifying:
<span>+1.5 + 0.4x=7/10

Simplifying:
<span>+1.5 + 0.4x=0.7

We move all terms containing x to the left and all other terms to the right.
<span> + 0.4x=0.7-1.5

We simplify left and right side of the equation.
<span> + 0.4x=-0.8

We divide both sides of the equation by 0.4 to get x.
<span>x=-2
                                                                                  


</span></span></span></span></span></span></span></span>
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Step-by-step explanation:

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\sf adjacent  = 4.5 \ ft

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Right triangles abc and dbc with right angle c are given below. If cos(a)=15,ab=12 and cd=2, find the length of bd.
dmitriy555 [2]

see the attached figure to better understand the problem

we have that

cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units

Step 1

<u>Find the value of AC</u>

we know that

in the right triangle ABC

cos (A)=(AC/AB)\\AC=AB*cos(A)

substitute the values in the formula

AC=12*(1/5)\\ AC=2.4\ units

Step 2

<u>Find the value of BC</u>

we know that

in the right triangle ABC

Applying the Pythagorean Theorem

AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}

substitute the values

BC^{2}=12^{2} -2.4^{2}\\BC^{2}= 138.24\\ BC=11.76\ units

Step 3  

<u>Find the value of BD</u>

we know that

in the right triangle BCD

Applying the Pythagorean Theorem

BD^{2} =DC^{2}+BC^{2}

substitute the values  

BD^{2} =2^{2}+11.76^{2}

BD=11.93\ units

therefore

<u>the answer is</u>

the length of BD is 11.93 units

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