Perímetro del rectángulo = 74 pulgadas
Deje que el ancho del rectángulo sea 'x'.
Entonces, la longitud de este rectángulo = x + 5
We know that :
![\color{hotpink}\tt \: Perímetro \: del \: rectángulo =\color{plum} 2 × (l + b)](https://tex.z-dn.net/?f=%5Ccolor%7Bhotpink%7D%5Ctt%20%5C%3A%20Per%C3%ADmetro%20%20%5C%3A%20del%20%5C%3A%20%20rect%C3%A1ngulo%20%3D%5Ccolor%7Bplum%7D%202%20%C3%97%20%28l%20%2B%20b%29%20)
Lo que significa :
![=\tt 2(x + x + 5) = 74](https://tex.z-dn.net/?f=%20%3D%5Ctt%202%28x%20%2B%20x%20%2B%205%29%20%3D%2074)
![=\tt 2(2x + 5) = 74](https://tex.z-dn.net/?f=%20%3D%5Ctt%202%282x%20%2B%205%29%20%3D%2074)
![=\tt 4x +10 = 74](https://tex.z-dn.net/?f=%20%3D%5Ctt%204x%20%2B10%20%3D%2074%20)
![=\tt 4x = 74 - 10](https://tex.z-dn.net/?f=%20%3D%5Ctt%204x%20%3D%2074%20-%2010)
![=\tt 4x = 64](https://tex.z-dn.net/?f=%20%3D%5Ctt%204x%20%3D%2064)
![=\tt x = \frac{64}{4}](https://tex.z-dn.net/?f=%20%3D%5Ctt%20x%20%3D%20%20%5Cfrac%7B64%7D%7B4%7D%20)
![\color{plum} =\tt x = 16](https://tex.z-dn.net/?f=%5Ccolor%7Bplum%7D%20%3D%5Ctt%20x%20%3D%2016)
Por lo tanto, el ancho de este rectángulo = 16 pulgadas
Entonces, la longitud de este rectángulo :
![=\tt x + 5](https://tex.z-dn.net/?f=%20%3D%5Ctt%20x%20%2B%205)
![= \tt16 + 5](https://tex.z-dn.net/?f=%20%3D%20%5Ctt16%20%2B%205)
![\color{plum} =\tt 21 \: pulgadas](https://tex.z-dn.net/?f=%5Ccolor%7Bplum%7D%20%3D%5Ctt%2021%20%5C%3A%20pulgadas)
La longitud de este rectángulo = 21 pulgadas
<h2>Por lo tanto :</h2>
● Longitud del rectángulo = <em>21 pulgadas</em>
● Ancho del rectángulo = <em>16 pulgadas</em>
The difference between both unit rates rounded off to the nearest tenth is: 0.4 meters per second
Step-by-step explanation:
We have to calculate his unit rate for both type of races
So,
<u>Unit rate for 400m race:</u>
Distance = 400m
Time = 43 sec
![Unit\ rate = U_1= \frac{Distance}{Time}\\=\frac{400}{43}\\=9.30\ meters\ per\ second](https://tex.z-dn.net/?f=Unit%5C%20rate%20%3D%20U_1%3D%20%5Cfrac%7BDistance%7D%7BTime%7D%5C%5C%3D%5Cfrac%7B400%7D%7B43%7D%5C%5C%3D9.30%5C%20meters%5C%20per%5C%20second)
<u>Unit rate for 300m Race:</u>
Distance = 300m
Time = 31 sec
![Unit\ Rate= U_2=\frac{300}{31}\\=9.68\ meters\ per\ second](https://tex.z-dn.net/?f=Unit%5C%20Rate%3D%20U_2%3D%5Cfrac%7B300%7D%7B31%7D%5C%5C%3D9.68%5C%20meters%5C%20per%5C%20second)
The difference between both unit rates is:
![U_2-U_1 = 9.68-9.30\\=0.38 => 0.4\ meters\ per\ sec](https://tex.z-dn.net/?f=U_2-U_1%20%3D%209.68-9.30%5C%5C%3D0.38%20%3D%3E%200.4%5C%20meters%5C%20per%5C%20sec)
Hence,
The difference between both unit rates rounded off to the nearest tenth is: 0.4 meters per second
Keywords: Unit rate, Speed
Learn more about unit rate at:
#LearnwithBrainly
Answer:
I think its c
Step-by-step explanation:
Answer:
d. Approximate the standard normal distribution with the Student's t distribution
(0.2199 ; 0.2327)
Step-by-step explanation:
Given that :
Sample size, n = 31
Sample mean, xbar = 0.2258
Sample standard deviation, s = 0.0188
Confidence interval (C. I) :
xbar ± margin of error
Margin of Error : Tcritical * s/sqrt(n)
Degree of freedom, df = n - 1 = 31 - 1 = 30
Tcritical value :
T0.05/2, 30 = 2.042
Margin of Error = 2.042 * 0.0188/sqrt(31)
Margin of Error = 0.0068949
C. I = 0.2258 ± 0.0068949
Lower boundary : (0.2258 - 0.006895) = 0.2189
Upper boundary : (0.2258 - 0.006895) = 0.2327
(0.2199 ; 0.2327)
The answer is 12/5
Remember: Soh;opposite over Hypotenuse Cah; Adjacent over Hypotenuse Toa; Opposite over Adjacent. SOH CAH TOA
Hope this helps! :)