Answer:
Explanation:
Algorithm design is the branch of discrete mathematics and computer science that deals with the research, development and implementation of sequential and asynchronous algorithms. ... An algorithm is simply a sequence of instructions; a recipe is an algorithm, and so is a list of driving instructions.
Answer:
current_price = int(input("Enter the current price: "))
last_months_price = int(input("Enter the last month's price: "))
print("This house is $" + str(current_price))
print("The change is $" + str(current_price - last_months_price) + " since last month")
print("The estimated monthly mortgage is ${:.2f}".format((current_price * 0.051) / 12))
Explanation:
Ask the user to enter the current price and last month's price
Print the current price
Print the change in the price, subtract the last month's price from the current price
Print the estimated monthly mortgage, use the given formula to calculate, in required format
Answer:
A computer network is a group of two or more computers that are linked together. Networks are usually used to share resources, exchange files or communicate with other users. so A
Explanation:
Answer: Site Link
Explanation: Site link is the type connection that is created for the different sites.It helps in the connectivity in the multiple site surrounding known as inter-site and transferring the traffic created by the replication activity.
Other options are incorrect because bridgehead servers is a device to control the domain,subnet is the part of the IP network and domain is used for the identification of address .Thus, the correct option is site link.
Answer:
- public static String bothStart(String text1, String text2){
- String s = "";
-
- if(text1.length() > text2.length()) {
- for (int i = 0; i < text2.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }else{
- for (int i = 0; i < text1.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }
- }
Explanation:
Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).
<em />
Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).
There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).
If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.
The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>
<em />
At the end, return the s as output (Line 21).
