Answer:
The solution code is written in Python 3.
- def convertDate(date_string):
-
- date_list = date_string.split("/")
-
- for i in range(0, len(date_list)):
- date_list[i] = int(date_list[i])
-
- return date_list
-
-
- print(convertDate('06/11/1930'))
Explanation:
Firstly, create a function convertDate() with one parameter, <em>date_string</em>. (Line 1).
Next, use the Python string <em>split()</em> method to split the date string into a list of date components (month, day & year) and assign it to variable <em>date_list</em>. (Line 3) In this case, we use "/" as the separator.
However, all the separated date components in the <em>date_list</em> are still a string. We can use for-loop to traverse through each of the element within the list and convert each of them to integer using Python<em> int() </em>function. (Line 5 - 6)
At last return the final date_list as the output (Line 8)
We can test our function as in Line 11. We shall see the output is as follow:
[6, 11, 1930]
60,436 is larger.
A byte is a sequence of 8 bits (enough to represent one alphanumeric character) processed as a single unit of information. A single letter or character would use one byte of memory (8 bits), two characters would use two bytes (16 bits).
