Answer:
Step-by-step explanation:
0.5x=208.8
x=417.6
Answer: 2.28%
Step-by-step explanation:
Given: An airport find that at the present time, the mean noise level is 103 decibels and the standard deviation is 5.4 decibels.
The distribution of noise levels(x) for all jets during takeoff over the neighborhood has a normal distribution.
The probability that jets have a noise level less than 92.2 decibels when taking off over this neighborhood will be :-

Hence, the percent of these jets have a noise level less than 92.2 decibels when taking off over this neighborhood = 2.28%
You need to use the y = mx + b formula which will get you to the answer
y = -x -2
Answer:
2. D
3. B
Step-by-step explanation: