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3 years ago

What is the area of the composite figure?( 20 points)

Mathematics

1 answer:

kicyunya [14]3 years ago

5 0

The answer is B. 20.285

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Network poll what do you usually do after school? sport/club practice 28% nap 11% work 6% homework 17% game 14% eat a snack 13%

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3 years ago

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

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3 years ago

What is the sale price 45% of 69.50

Zolol [24]

x 55
-------- = ---------
69.50 100

69.50*55= 3822.5
3822.5/100= 38.225
x=$38.22

5 0

3 years ago

If P=Q^R , Q=R^P , R=P^Q. Then Prove: P×Q×R=1.

8_murik_8 [283]

Answer:

PQR=1

Step-by-step explanation:

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3 years ago

Need help on range and domain

SashulF [63]

Answer:

domain is your x value, and range is your y value.

Step-by-step explanation:

6 0

3 years ago

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What is the area of the composite figure?( 20 points)​

What is the area of the composite figure?( 20 points)