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CaHeK987 [17]
3 years ago
5

You are enrolled in a wellness course at your college. You achieved grades of 70, 86, 81, and 83 on the first four exams. The fi

na exam counts the same as an exam given during the semester. A.) If x represents the grade on the final exam, write an expression that represents your course average (arithmetic mean). B.) If your average is greater than or equal to 80 and less than 90, you will earn a B in the course. Using the expression from part A for your course average, write a compound inequality that must be satisfied to earn a B.
Mathematics
1 answer:
Ilya [14]3 years ago
4 0
Note that there are 5 exams altogether:  4 hour exams and 1 final exam.  Let the grade on the final be x.

The arith. mean of these 5 grades would be
                                                                        <span>70+ 86+ 81 + 83 + x
</span>                   course grade = arith. mean = -------------------------------------
                                                                                        5
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What is 2 1/8 take away 1/2​
goblinko [34]

The equation is 2\frac{1}{8} - \frac{1}{2} .

1/2 is equivalent to 4/8, and 2 1/8 is equal to 17/8. (two full sets of 8 + 1 = 8 + 8 + 1, or 17)

The new equation is \frac{17}{8} -\frac{4}{8} . Subtract the numerators.

17 - 4 = 13 or 13/8

The improper fraction \frac{13}{8} simplifies to 1\frac{5}{8} .

<h2>Answer:</h2>

1\frac{5}{8}

Hope this helps :)

5 0
3 years ago
You can represent and odd integer with the expression 2n + 1, where n is any integer. write and solace and equation to find thre
Wittaler [7]

As consecutive odd numbers differ by two (example: 3, 5, 7), the first odd number can be expressed as 2n + 1, the next can be found by adding two to the first to get 2n + 1 + 2 which simplifies to 2n + 3. Finally the expression for the third consecutive odd integer can be found by adding two to the previous, 2n + 3, to get 2n + 5.  Adding these three together and setting them equal to your sum gets the equation

 2n + 1 + 2n + 3 + 2n + 5 = 63

 Combine like terms and solve For n.

Once you have n, you must substitute it back into your three expressions (2n + 1, 2n + 3, 2n + 5) to find the three odd integers.  

 

Hope this helps :)

7 0
3 years ago
Printed circuit cards are placed in a functional test after being populated with semiconductor chips. A lot contains 140 cards,
Ray Of Light [21]

Answer:

The probability that at least 1 defective card is in the sample is 0.9644

Step-by-step explanation:

Here

N = 140

and n = 20

We will use the below given formula

P(at least 1 defective) = 1 - P( 0 defectives)

P( 0 defectives) =

= \frac{^{20}C_0 * ^{120}C_{20}}{ ^{140}C_{20}}\\= 0.0356 1-0.0356 \\= 0.9644

5 0
3 years ago
Round 0.195 to the nearest hundredth
Mila [183]
<span>Round 0.195 to the nearest hundredth = 0.20</span>
5 0
4 years ago
Read 2 more answers
I WILL GIVE BRAINLIEST HELP
Anika [276]
There you go it’s not Oscar but it’s the same question

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3 years ago
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