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CaHeK987 [17]
3 years ago
5

You are enrolled in a wellness course at your college. You achieved grades of 70, 86, 81, and 83 on the first four exams. The fi

na exam counts the same as an exam given during the semester. A.) If x represents the grade on the final exam, write an expression that represents your course average (arithmetic mean). B.) If your average is greater than or equal to 80 and less than 90, you will earn a B in the course. Using the expression from part A for your course average, write a compound inequality that must be satisfied to earn a B.
Mathematics
1 answer:
Ilya [14]3 years ago
4 0
Note that there are 5 exams altogether:  4 hour exams and 1 final exam.  Let the grade on the final be x.

The arith. mean of these 5 grades would be
                                                                        <span>70+ 86+ 81 + 83 + x
</span>                   course grade = arith. mean = -------------------------------------
                                                                                        5
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3 years ago
Yˆ=2.391x+57.420 which number is the y intercept?
BaLLatris [955]

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57.420

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The y intercept is always the number on the out side next to the slope which is 2.391

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Which ordered pair is generated from the equation shown below?
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A

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Side AB is 18, Side AC is 9, Side BC is 5. Find the SinA. Give your answer in fraction and decimal form.
Sladkaya [172]

Input data

In any right triangle, the sine of an angle x is the length of the opposite side (O) divided by the length of the hypotenuse (H). In a formula, it is written as 'sin' without the 'e':

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7 0
1 year ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
4 years ago
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