How many six-digit odd numbers are possible if the leftmost digit cannot be zero
1 answer:
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Answer: <RPS = 161
Step-by-step explanation:
P is the common vertex in all of these angles. From this we know that these have to be adjacent angles (<QPR and <QPS) that equal the whole angle (<RPS)
<QPR+<QPS= <RPS
71+90= 161
(<QPS is a right angle. Right angles are equal to 90 degrees.)
