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xxMikexx [17]
3 years ago
9

I only need a little bit of help. PLS HELP

Mathematics
1 answer:
svetlana [45]3 years ago
8 0

Answer:

Step-by-step explanation:

15. (x + 6)(x + 1)

16. (m - 19)(m + 2)

17. (y - 8)(y - 2)

18. (p + 12)(p - 3)

19. (c - 15)(c + 3)

20. (w - 8)^2

21. (a + 15)(a - 2)

22. (x - 30)(x + 3)

23. 3(5r + 4)(5r - 4)

24. 5(3x - 1)(3x + 1)

25. m^2n(1 - n)(1 + n)

26. 6a(a - 2b)(a + 2b)

27. 3(x^2 + 5x - 24)

      3(x + 8)(x - 3)

28. 2(m - 1)^2

29. x(x^2 + 9x - 52)

       x(x+13)(x-4)

30. 4y(y^2+y-30)

       4y(y+6)(y-5)

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fomenos

Answer:

x³+57

step by step explanation

8 0
3 years ago
25 is what percent less than 35
mars1129 [50]
Difference between 25 and 35 = 35 -25
                                                 = 10
Then
percentage by which 25 is less than 35 =(10/35) * 100
                                                                 = (2/7) * 100
                                                                 = 200/7
                                                                 = 28.57 percent
So 25 is 28.57% less than 35.This is the only clear way of solving these kind of problems. I hope you have understood the method used to solve this problem. Hopefully you can do such type of problems without needing any help.
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What is the slope of the line containing(-3,5) and (6,-1)
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Please solve Questions - 18 , 20 , 21 <br>Show proper work. Thank-you!
Ymorist [56]
18. If f(x)=[xsin πx] {where [x] denotes greatest integer function}, then f(x) is:
since x denotes the greatest integers which could the negative or the positive values, also x has a domain of all real numbers, and has no discontinuous point, then x is continuous in (-1,0).

Answer: B]

20. Given that g(x)=1/(x^2+x-1) and f(x)=1/(x-3), then to evaluate the discontinuous point in g(f(x)) we consider the denominator of g(x) and f(x). g(x) has no discontinuous point while f(x) is continuous at all points but x=3. Hence we shall say that g(f(x)) will also be discontinuous at x=3. Hence the answer is:
C] 3

21. Given that f(x)=[tan² x] where [.] is greatest integer function, from this we can see that tan x is continuous at all points apart from the point 180x+90, where x=0,1,2,3....
This implies that since some points are not continuous, then the limit does not exist.
Answer is:
A]


3 0
3 years ago
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