Answer:
We have 40% antifreeze and 70% antifreeze and we need to make 240 liters of 64% antifreeze.
We set up 2 equations where "f" is the 40 % and "s" is the 70%
A) f + s = 240
B) .40f + .70s = (.64 * 240) (or 153.6)
To solve both equations we multiply A) by -.40
A) -.40 f - .40 s = -96.00 then we add this to B)
B) .40f + .70s = 153.60
.30s = 57.6
s = 192
f = 48
48 liters of 40% = 19.20 liters of antifreeze
192 liters of 70% = 134.40 liters of antifreeze
That equals 153.60 liters of antifreeze in a TOTAL liquid amount of 240 liters.
Double Check
153.60 / 240 = 64% antifreeze.
Step-by-step explanation:
We are subtracting 3 * 47.36 from 530.2
3 * 47.36 = <span>142.08
</span>
530.2 - 142.08 = <span>388.12
Your answer should be </span><span>388.12 grams left. Hope this helps!</span>
I think it’s d for the standard equation
Answer:
-3.8, 3
Step-by-step explanation:
The solution to a system is where the graph cross each other. If you look to where they intersect to the left of the origin, where x is negative, it appears that they intersect ALMOST at -4, but not quite. So -3.8 is going to have to do since we don't have the equations of either graph to find the exact values of x. To the right of the origin, where x is positive, the graphs cross where x = 3..
3/20 = 1.5/10 = 15/100
Hope this helps!
