Answer:
What is the question?
Step-by-step explanation:
1. Write all of the question to receive a correct answer.
Answer:
plug in 0 for y and solve for x
to find y plug in 0 for x
Step-by-step explanation:
Answer:
Step-by-step explanation:
![\frac{x^3}{a^3} +\frac{a^3}{x^3} =p\\\frac{x^3}{a^3} -\frac{a^3}{x^3} =q\\adding\\2\frac{x^3}{a^3} =p+q\\\frac{x^3}{a^3} =\frac{p+q}{2} \\substitute~in~first\\\frac{p+q}{2} +\frac{2}{p+q} =p\\\frac{(p+q)^2+4}{2(p+q)} =p\\(p+q)^2+4=2p(p+q)\\p^2+q^2+2pq+4-2p^2-2pq=0\\q^2-p^2+4=0\\q^2=p^2-4](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E3%7D%7Ba%5E3%7D%20%2B%5Cfrac%7Ba%5E3%7D%7Bx%5E3%7D%20%3Dp%5C%5C%5Cfrac%7Bx%5E3%7D%7Ba%5E3%7D%20-%5Cfrac%7Ba%5E3%7D%7Bx%5E3%7D%20%3Dq%5C%5Cadding%5C%5C2%5Cfrac%7Bx%5E3%7D%7Ba%5E3%7D%20%3Dp%2Bq%5C%5C%5Cfrac%7Bx%5E3%7D%7Ba%5E3%7D%20%3D%5Cfrac%7Bp%2Bq%7D%7B2%7D%20%5C%5Csubstitute~in~first%5C%5C%5Cfrac%7Bp%2Bq%7D%7B2%7D%20%2B%5Cfrac%7B2%7D%7Bp%2Bq%7D%20%3Dp%5C%5C%5Cfrac%7B%28p%2Bq%29%5E2%2B4%7D%7B2%28p%2Bq%29%7D%20%3Dp%5C%5C%28p%2Bq%29%5E2%2B4%3D2p%28p%2Bq%29%5C%5Cp%5E2%2Bq%5E2%2B2pq%2B4-2p%5E2-2pq%3D0%5C%5Cq%5E2-p%5E2%2B4%3D0%5C%5Cq%5E2%3Dp%5E2-4)
Answer:
Dr hmm fruncfyhn
Step-by-step explanation:
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