PLEASE HELP ME!!!! What is 567-58y+375-56=13c-5s-456x249=? I NEED HELP!!

Find the lateral area of the come in terms of pi.

Norma-Jean [14]

The answer should be 12x cm power of 2

4 0

3 years ago

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9x-8(x-6)=52 what is the answer

Effectus [21]

Answer:

x = 4

Step-by-step explanation:

Step 1: Write equation

9x - 8(x - 6) = 52

Step 2: Solve for x

Distribute -8: 9x - 8x + 48 = 52
Combine like terms: x + 48 = 52
Subtract 48 on both sides: x = 4

Step 3: Check

Plug in x to verify it's a solution.

9(4) - 8(4 - 6) = 52

36 - 8(-2) = 52

36 + 16 = 52

52 = 52

7 0

3 years ago

Plz help me I only have 5 minutes left winner gets brainliest

solniwko [45]

Answer is number three

3 0

2 years ago

The probability density function of the time to failure of an electronic component in a copier (in hours) is f(x) for Determine

salantis [7]

The question is incomplete. Here is the complete question.

The probability density function of the time to failure of an electronic component in a copier (in hours) is

$f(x)=\frac{e^{\frac{-x}{1000} }}{1000}$

for x > 0. Determine the probability that

a. A component lasts more than 3000 hours before failure.

b. A componenet fails in the interval from 1000 to 2000 hours.

c. A component fails before 1000 hours.

d. Determine the number of hours at which 10% of all components have failed.

Answer: a. P(x>3000) = 0.5

b. P(1000<x<2000) = 0.2325

c. P(x<1000) = 0.6321

d. 105.4 hours

Step-by-step explanation: Probability Density Function is a function defining the probability of an outcome for a discrete random variable and is mathematically defined as the derivative of the distribution function.

So, probability function is given by:

P(a<x<b) = $\int\limits^b_a {P(x)} \, dx$

Then, for the electronic component, probability will be:

P(a<x<b) = $\int\limits^b_a {\frac{e^{\frac{-x}{1000} }}{1000} } \, dx$

P(a<x<b) = $\frac{1000}{1000}.e^{\frac{-x}{1000} }$

P(a<x<b) = $e^{\frac{-b}{1000} }-e^\frac{-a}{1000}$

a. For a component to last more than 3000 hours:

P(3000<x<∞) = $e^{\frac{-3000}{1000} }-e^\frac{-a}{1000}$

Exponential equation to the infinity tends to zero, so:

P(3000<x<∞) = $e^{-3}$

P(3000<x<∞) = 0.05

There is a probability of 5% of a component to last more than 3000 hours.

b. Probability between 1000 and 2000 hours:

P(1000<x<2000) = $e^{\frac{-2000}{1000} }-e^\frac{-1000}{1000}$

P(1000<x<2000) = $e^{-2}-e^{-1}$

P(1000<x<2000) = 0.2325

There is a probability of 23.25% of failure in that interval.

c. Probability of failing between 0 and 1000 hours:

P(0<x<1000) = $e^{\frac{-1000}{1000} }-e^\frac{-0}{1000}$

P(0<x<1000) = $e^{-1}-1$

P(0<x<1000) = 0.6321

There is a probability of 63.21% of failing before 1000 hours.

d. P(x) = $e^{\frac{-b}{1000} }-e^\frac{-a}{1000}$

0.1 = $1-e^\frac{-x}{1000}$

$-e^{\frac{-x}{1000} }=-0.9$

${\frac{-x}{1000} }=ln0.9$

-x = -1000.ln(0.9)

x = 105.4

10% of the components will have failed at 105.4 hours.

5 0

3 years ago

Andrea is shopping for items for her pet sitting business because the store is having a sale where everything in the store

frutty [35]

Answer:

the answer is the first one

Step-by-step explanation:

39.99 rounded up is 40.00

19.99 rounded up is 20.00

40.00*0.05 = 2, 40-2 = 38

20.00*0.15 = 3, 20-3 = 17*.05 = 0.85, 17-0.85 = 16.15

38+16.15 = 54.15

5 0

3 years ago

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