Question

8 Express sin A, cos A, and tan A as ratios. 12 613

Answer 1

Answer:

see explanation

Step-by-step explanation:

sinA = $\frac{opposite}{hypotenuse}$ = $\frac{BC}{AB}$ = $\frac{6\sqrt{3} }{12}$ = $\frac{\sqrt{3} }{2}$

cosA = $\frac{adjacent}{hypotenuse}$ = $\frac{AC}{AB}$ = $\frac{6}{12}$ = $\frac{1}{2}$

tanA = $\frac{opposite}{adjacent}$ = $\frac{BC}{AC}$ = $\frac{6\sqrt{3} }{6}$ = $\sqrt{3}$