Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
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Answer:
The slope is -10, and the y-intercept is 1.
Step-by-step explanation:
Assuming that the equation is y = -10x+1, the easiest way to identify slope and the y-intercept is by knowing the equation for slope-intercept (y = mx+b)
Equation for slope-intercept (y = mx+b) explained:
The equation is y = mx+b, let's break it down.
y = The line
m = The slope
b = The y-intercept
Now that we know the equation and broke it down you can identify them in your equation
Slope (m)= -10
y-intercept = 1
Conclusion: The slope is -10, and the y-intercept is 1.
Answer: Im Not really sure but the answer is 303.66
Step-by-step explanation: A=a+b
2h=19+29.2
2·12.6=303.66
Answer:
assuming no doors or windows & that 5m is height:
4 walls = 4.67
roof = 2.4
Step-by-step explanation:
area of walls = 2(8x5)+2(6x5) = 140 m^2
140/30 = 4.67
area of roof = 8x6 = 48 m^2
48/20 = 2.4
