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3 years ago

HELP HELP PLS HELP I WILL BRAINLIST U

Mathematics

1 answer:

elena55 [62]3 years ago

5 0

Answer:

y-3x=-1

2x+y-(y-3x)=4-(-1)

2x+y-y+3x.=4+1

5x =5

x=1

y=(3×1)-1,

y=3-1

y=2

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in the second half of the game, the Wildcats again scored 18 points. This time, however, we don't know how many total shots were

Kobotan [32]

Lets start with the chain of 3's:

18 = 3 + 3 + 3 + 3 + 3 + 3

But, we know that

3 + 3 = 2 + 2 + 2

Sol, let's replace 3 + 3 by 2 + 2 + 2 one by one.

Hence, the possible ways of combinations are listed below:

18 = 3 + 3 + 3 + 3 + 2 + 2 + 2 (1)

18 = 3 + 3 + 2 + 2 + 2 + 2 + 2 + 2 (2)

Therefore, there are two combinations of 2- and 3- point shots that could total 18 points.

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3 years ago

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Alexxandr [17]

Answer

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3 years ago

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What is the solution to -2(8x – 4) < 2x + 5? він x x оооо x x заще х: 6 о

lozanna [386]

Answer:

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3 years ago

8. How many ways can a committee of 5 students be chosen from a student council of 30 students? Is the order in which the member

tankabanditka [31]

Answer: A committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

No , the order in which the members of the committee are chosen is not important.

Step-by-step explanation:

Given : The total number of students in the council = 30

The number of students needed to be chosen = 5

The order in which the members of the committee are chosen does not matter.

So we Combinations (If order matters then we use permutations.)

The number of combinations of to select r things of n things = $^nC_r=\dfrac{n!}{r!(n-r)!}$

So the number of ways a committee of 5 students can be chosen from a student council of 30 students= $^{30}C_5=\dfrac{30!}{5!(30-5)!}$

$=\dfrac{30\times29\times28\times27\times26\times25!}{(120)\times25!}=142506$

Therefore , a committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

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3 years ago

A 33 - m tall building casts a shadow. The distance from the top of the building to the tip of the shadow is 37 m . Find the len

ArbitrLikvidat [17]

This is Pythagorean theorem, a^2+b^2=c^2 , a = 33 and c = 37 so b^2 + 1089 = 1369 , b^2 = 280 , b = 16.73m

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