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jek_recluse [69]
3 years ago
13

If the expression 2xy^{-2}{4xy^2} is written in the form ax^by^c, then what is the product of a b and c?

Mathematics
1 answer:
Gre4nikov [31]3 years ago
3 0

Answer: The product of a b and c is 0.

Step-by-step explanation:

The given expression : 2xy^{-2}{4xy^2}

=2\times4x^{1+1}y^{-2+2}\ \ \ \  [\text{Property of exponents: } a^m\times a^n=a^{m+n}]

=8x^2y^0

When we compare this to ax^by^c, we get a=8, x=2, y=0

The product of a, b and c = a\times b \times c

=8\times2\times0\\\\=0

The product of a b and c is 0.

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Do this to get brainiest!<br><br> (click on the image to see clearly)
Anna71 [15]

Answer:

8) 4(n)+12

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8 0
3 years ago
5. The rate of change in revenue for the Priceline Group from 2004 to 2013 can be modeled
Mumz [18]

Answer:

a ) R(x)  = 0,2933*e∧0,2387*t

b) 5,9042 billions of dollars

Step-by-step explanation:

The rate of change in revenue  dR/dt for Priceline Group is

dR/dt =  0,07*e∧0,2387*t

dR = (0,07*e∧0,2387*t ) * dt

∫dR = ∫ (0,07*e∧0,2387*t ) * dt       between 2004  to 2013   ( t = 4 stands for 2004 and t = 13 stands for 2013 )

R(x)  =  (0,07/ 0,2387)*e∧0,2387*t )

R(x)  = 0,2933*e∧0,2387*t

Then

R(4)  = 0,2933*e∧0,2387*4

R(4) =  0,2933*2,5981

R(4) =  0,7602 billions of dollars

R(12)  = R(4) +   0,2933*e∧0,2387*12

R(12)  = 0,7602 +  5,1440

R(12)  =  5,9042 billions of dollars

8 0
3 years ago
X^4 + 25 = 26x^2<br><br>please answer quick. I'll give brainliest rothe first person​
Shalnov [3]

{ \leadsto{ \sf{ \green{ {x}^{4}  + 25 = 26 {x}^{2} }}}} \\  \\ { \leadsto{ \sf{ \green{ {x}^{4}  - 26 {x}^{2}  + 25 = 0}}}} \\  \\ { \sf{ \underline{ \blue{let  \:  \: {x}^{2} \:  be \: equal \: to \: a}}}}

{ \leadsto { \green{ \sf{ {a}^{2}  - 26a + 25 = 0}}}} \\  \\ { \leadsto{ \green{ \sf{ {a}^{2}  - (a + 25a) + 25 = 0}}}} \\  \\ { \leadsto{ \green{ \sf{ {a}^{2}  - a - 25a + 25 = 0}}}} \\  \\ { \leadsto{ \green{ \sf{a(a - 1) - 25(a - 1) = 0}}}}

{ \leadsto{ \sf{ \green{(a - 1)(a - 25) = 0}}}} \\  \\ { \sf{ substituting \: value \: of \: a}} \\  \\ { \rightarrow{ \sf{ \blue{( {x}^{2}  - 1)( {x}^{2}  - 25) = 0}}}} \\  \\ { \sf {{x}^{2}  = 1}}  \\ { \sf{ \underline{x = \: ±  \: 1}}} \\  \\  \\ { \sf {x}^{2}  = 25}  \\ { \sf{ \underline{x =  \: ± \: 5}}}

7 0
3 years ago
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