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OLga [1]
3 years ago
11

A sea lion dove from the water's surface at sea level to an altitude of −216.12 meters in 2.4 minutes.

Mathematics
2 answers:
prohojiy [21]3 years ago
8 0
Your answer is -90.05! :)))

xenn [34]3 years ago
8 0

Answer:

The average change in the sea lion's altitude is -90.05 m/min.

Step-by-step explanation:

We have been given the altitude as −216.12 meters and the time taken in 2.4 minutes.

The average change in the sea lion's altitude is given by

\text{average change}=\frac{\text{Altitude}}{\text{time}}

On substituting the known values, we get

\text{average change}=\frac{-216.12}{2.4}\text{ m/min}\\\\\text{average change}=-90.05

Therefore, the average change in the sea lion's altitude is -90.05 m/min.

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Answer:

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Step-by-step explanation:

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x = -9

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x

to the left side of the equation.

4

x

−

4

=

20

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x

to the right side of the equation.

4

x

=

24

divide each term by 4

x = 6

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2(x−3)=−20

2x−6=−20

Step 2: Add 6 to both sides.

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Step 3: Divide both sides by -4.

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