The answer to the first problem is x=1
The answer to the 2nd problem is x=4
In the first problem, you need to subtract the 8 from both sides of the equation then divide 4 by both sides which makes 4 cancel itself out leaving x and 12 leaving 1.
The width is x
<span>The length is x+60 </span>
<span>so x(x+60) = 16000
</span>
<span>x^2 + 60x = 16000
</span>
<span> </span>
<span>x^2 + 60x + 900 = 900+16000
</span>
<span>(x+30)^2 = 16900
</span><span> </span>
<span>x+30 = 130
</span>
<span>x = 100
So your answer is 100. </span>
All parts of arithmetic equations have names. In an addition equation, addends are the numbers that are added together to give a sum. In a subtraction equation, the subtrahend is taken away from the minuend to give a difference. In a multiplication equation, factors are multiplied to give a product.
Answer:
See explanation
Step-by-step explanation:
Assuming we want to solve for x in:
Then we factor to get:
Apply the zero product principle to get:
The question is not all that clear, so I assume you are solving for x in the completed quadratic equation.
