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irina1246 [14]
4 years ago
12

Which part of an ecuation is the sum

Mathematics
1 answer:
erastova [34]4 years ago
7 0
All parts of arithmetic equations have names. In an addition equation, addends are the numbers that are added together to give a sum. In a subtraction equation, the subtrahend is taken away from the minuend to give a difference. In a multiplication equation, factors are multiplied to give a product.
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Complete Question

The complete question is shown on the first uploaded image

Answer:

a

      P(U |D ) = 0.198

b

   P(O\ n \ B) = 0.188

c

  P(O | B) =   0.498

Step-by-step explanation:

The total number of deaths is mathematically represented as

      T   =  16 +  23 + \cdots  +  16

        T   =623

The total number of deaths in 1996 - 2000 is mathematically represented as

     T_a =  16 +  23+ \cdots + 30

      T_a = 235

The total number of deaths in 2001 - 2005 is mathematically represented as

     T_b =  17 +  16 + \cdots + 23

      T_b = 206

The total number of deaths in 2006 - 2010 is mathematically represented as

     T_c =  15 +  17 + \cdots + 16

      T_d = 182

Generally the the probability that it would occur under the tree given that the death was  after  2000 is mathematically represented as

     P(U |D ) = \frac{P(A \ n\  U )}{P(A)}

Here  P(A \ n\  U ) represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

         P(A \ n\  U )   = \frac{Z}{ T}

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

         Z =  35 +  42

=>       Z =  77

=>       P(A \ n\  U )   = \frac{77}{ 623}

=>      

Also

     P(A) is the probability of the death occurring after 2000  and this is mathematically represented as

        P(A) =  \frac{T_b  +  T_c}{ T}

=>      P(A) =  \frac{ 206+  182}{623}

=>  

So

         P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+  182}{623}}

=>      P(U |D ) = 0.198

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

      P(O | B) = \frac{T_z}{ T}

Here T_z is the total number of death outside / camping before 2001  and the value is  117  

So

            P(O \ n \ B) = \frac{117}{623}

=>          P(O\ n \ B) = 0.188

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

       P(O | B) =  \frac{ P( O \ n \ B)}{ P(B)}

Here P(B) is the probability that it was before 2001 , this is mathematically represented as  

          P(B ) =  \frac{T_a}{T}

=>       P(B ) =  \frac{235}{623}

So

          P(O | B) =  \frac{ \frac{117}{623}}{ \frac{235}{623}}

=>       P(O | B) =   0.498

5 0
3 years ago
The monthly output P of a light bulb factory is given by the formula P = 450LK, where L is the amount invested in labor and K th
Tems11 [23]

Answer:

C(p)  = 4,96 (in thousands of dollars)

l = 2980 $  invest in labor

k = 2980 $ invest in equipment

Step-by-step explanation:

Information we have:

Monthly output   P = 450*l*k       ⇒  k = P/450*l

But the production need to be 4000

Then k = 4000/450*l

Cost of production = l * k     (in thousands of dollars)

C(l)  =  l  + 4000/450*l

Taking derivatives (both members of the equation)

C´(l) = 1 - 400 /45*l²          ⇒ C´(l) = 0          ⇒ 1 - 400/45l²  = 0

45*l² -  400  = 0              ⇒  l²  = 400/45

l = 2.98 (in thousands of dollars)

l = 2980 $ And

k = 400/45*l           ⇒  k 400/45*2.98

k = 2.98  (in thousands of dollars)

C(p) = l + k

C(p)  =  2980 + 2980  

C(p)  = 5960 $

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Compare one third to sixths
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