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lions [1.4K]
3 years ago
9

The differential equation y′′=0y′′=0 has one of the following two parameter families as its general solution: yyyy=C1ex+C2e−x=C1

cos(x)+C2sin(x)=C1tan(x)+C2sec(x)=C1+C2xy=C1ex+C2e−xy=C1cos⁡(x)+C2sin⁡(x)y=C1tan⁡(x)+C2sec⁡(x)y=C1+C2x Find the solution such that y(0)=6y(0)=6 and y′(0)=9y′(0)=9.
Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

y(x)=6+9x

Step-by-step explanation:

Given differential equation, y''=0

Characteristic equation is given by m^2=0

\Rightarrow m=0,0.

Differential equation have repeated roots and solution of differential equation is y(x)=C_1+C_2x.............................(1)

Initial conditions are y(0)=6,y'(0)=9

Plugging first condition in equation (1),

6=C_1+C_2(0)

C_1=6

Equation (1) becomes

y(x)=6+C_2x............................(2)

differentiate equation (2) with respect to 'x',

y'(x)=C_2

Plugging second condition,

C_2=9

Hence, y(x)=6+9x

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