Awnser this question plz

M∠3 + m∠6 =180° True or False?

Natali5045456 [20]

Answer:

False. Because it is the answer.

8 0

3 years ago

Read 2 more answers

Show the following numbers on number line 3/2, 5/2, -3/2

pav-90 [236]

When you create the number line, put 0 in the middle. Basically you put all the numbers you got from least to greatest on the number.

Since -3/2 is less than 0, it will go to the left of 0.

Since 3/2 and 5/2 are greater than 0, it will go to the right of 0.

Remember to use sub points of 1.

Best of Luck!

3 0

3 years ago

Brent leaves school to go home. He walks 10 blocks north and then 6 blocks west. If Brent could walk in a straight line to the s

Alja [10]

<h2>8 BLOCKS :)))</h2>

:)))) NO NEED SOLUTION.

6 0

2 years ago

A manufacturer of tires wants to advertise a mileage interval that ex-cludes no more than 10% of the mileage on tires he sells.

Sergio039 [100]

Answer:

This mileage interval is from 30120 miles and higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

All he knows is that, for a large number of tires tested, the mean mileage was 25,000 miles, and the standard deviation was 4000 miles. This means that $\mu = 25000, \sigma = 4000$ .

A manufacturer of tires wants to advertise a mileage interval that ex-cludes no more than 10% of the mileage on tires he sells. What interval wouldyou suggest?

The lower end of this interval is X when Z has a pvalue of 0.90. That is $Z = 1.28$ .