Answer:
Step-by-step explanation:
10) Triangle ABC is similar to triangle EDC. This means that
AB/ED = BC/DC = AC/EC
Therefore,
(3x - 5)/32 = (5x - 5)/56
Cross multiplying, it becomes
56(3x - 5) = 32(5x - 5)
168x - 280 = 160x - 160
168x - 160x = 280 - 160
8x = 120
x = 120/8 = 15
11) Triangle JKL is similar to triangle triangle MKN. This means that
JK/MK = KL/KN = JL/MN. Therefore,
32/12 = (3x - 2)/(x + 1)
Cross multiplying, it becomes
32(x + 1) = 12(3x - 2)
32x + 32 = 36x - 24
36x - 32x = 32 + 24
4x = 56
x = 56/4 = 14
12) Triangle BCD is similar to triangle GEF. This means that
BC/GE = CD/EF = BD/GF. Therefore,
(x + 4)/51 = (2x - 7)/57
Cross multiplying, it becomes
57(x + 4) = 51(2x - 7)
57x + 228 = 102x - 357
102x - 57x = 228 + 357
45x = 585
x = 585/45 = 13
Answer:
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Step-by-step explanation:
Here is a system of linear equations that represents the situation.
x +5y +10z +20w = 133 . . . total amount earned
x +y +z +w = 39 . . . . . . . . . total number of bills
y = 4z . . . . . . . . . . . . . . . . . . the number of 5s is 4 times the number of 10s
x = 2y -1 . . . . . . . . . . . . . . . . the number of 1s is 1 less than twice the number of 5s
_____
We can substitute for x and z in the first two equations:
... (2y-1) +5y +10(y/4) +20w = 133
... (2y-1) +y +(y/4) +w = 39
These simplify to
... 9.5y +20w = 134
... 3.25y +w = 40
Solving by your favorite method, you get
... y = 12
... w = 1
So the other values can be found to be
... x = 2·12 -1 = 23
... z = 12/4 = 3
The solution to the system is (x, y, z, w) = (23, 12, 3, 1).
Answer:
246
Step-by-step explanation:
In the statment is defined our Values.
First que have a 95% Confidence interval
That is exactly in a Standar normal distribution table equal to Z Score = 1.96
The proportion
= 0.20
And we can and Margin Error (ME) equal to 0.05
Using the formula for the Sample Size (N) through Proportion we have,


or 246