<u>Answer:
</u>
Two required integers are 5 and 10.
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Solution:
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Given that a positive integer is twice another. The sum of the reciprocals of the positive integers is
We have to find the two integers.
Let assume that one integer = x
Since another integer is twice of first one, so second integer = 2x
Reciprocal of first integer =
Reciprocal of first integer =
Given that sum of reciprocal =
On solving above equation for x,
2x=10
x=5
First integer = x = 5
Second integer = 2x = 10
Hence two required integers are 5 and 10.
<h3>
Answer: 1320 (choice C)</h3>
Explanation:
There are 12 choices for left field.
Then there are 12-1 = 11 choices for right field.
Lastly, there are 11-1 = 10 choices for center field.
In total we have 12*11*10 = 1320 different permutations or orderings.
Answer:
A,C,D. those 3 have a percent error of less then 15%
Simplify 2.8y + 6 + 0.2y to 3y + 6
subtract 3y from both sides
simplify 5y - 15 - 3y to 2y - 15
add 15 to both sides
simplify 6 + 15 to 21
divide both sides by 2
switch sides
Answer: y = 21/2
*in decimal form this would be 10.5
Answer:
false
Step-by-step explanation: