I assume that it’s an equation so:
2x^3-4=0
x=(2)^(1/3)
Polynomial division yields

As

, you have the remainder term approaching

, so the horizontal asymptote is the line

.
Answer:
2x^2yz + 3xy^3z - 3xyz^3
Step-by-step explanation:
First you must distribute:
xyz(2x) + xyz(3y^2) + xyz(-3z^2)
Then simplify:
2xyxx + 3xyzy^2 - 3xyz * z^2
And finally simplify each term:
2x^2yz + 3xy^3z - 3xyz^3
2x^2y√6x
the image has the answer in a mor clear form
Answer:
I think that it is a quadratic