0.03 compare to 0.003
While comparing decimals we write the decimals one below the other according to the place value of each digits in place value chart
ones -- point -- Tenths -- Hundredths -- Thousandths
0 . 0 3
0 . 0 0 3
Now we compare each digit left to right. We have 3 in hundredths and 0 in hundredths place. 3 is greater
So 0.03 is greater than 0.003
0.03 > 0.003
Answer: A
Step-by-step explanation: SORRY IF I GET IT WRONG
This question is incomplete, the complete question is;
For integers a, b and k, we know that a > 12, b < 20 and a < b. If b=7k, what is the value of k ?
Answer: the value of k = 2
Step-by-step explanation:
Given that;
a > 12
b < 20
a < b
If b = 7k
Now if k = 1 {b = 7k = 7}
b would be equal to 7 but b has to be greater than 20
IT CANT BE
if k = 2 { b = 7k = 14}
b would be equal to 14, a is greater than 12, b has to be less than b; 14 < 20,
a has to be less than than b ( 12 < 14 )
IT IS
if k = 3 {b = 7k = 21}
b would be equal to 21, so b is greater than 20 and a is less than 21
IT CANT BE
Therefore the value of k = 2
The required matrix is:
![\left[\begin{array}{ccc}-25&17&0\\8&-1&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-25%2617%260%5C%5C8%26-1%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
We need to apply elementary row operation -2R₂+3R₁ tothe matrix:
![A=\left[\begin{array}{ccc}-3&5&2\\8&-1&3\\\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%265%262%5C%5C8%26-1%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Multiplying Row 2 with -2 and Row1 with 3 and adding,
-9 15 6
-16 2 -6
----------
-25 17 0
After applying this operation, Row 1 will be changed while Row 2 will remain same because we get -2R₂+3R₁ -> R₁
The required matrix is:
Keywords: Matrices, elementary row operation
Learn more about matrices at:
#learnwithBrainly
Step-by-step explanation:
g=m+13
g+m=113
use substitution
