Question

Dylan has a square peice of metal that measures 10inches on each side he cuts the metal along the diagonal, forming two right trianhles what is the the length of the hypotenuse of each right triangle to the nearest tenth of an inch

Answer 1

Since it is a square, both the length and the width are equal. Both are 10 inches.

We will use Pythagoras Theorem to find the diagonal of the square.

$\boxed { \boxed {a^2 + b^2 = c^ }}$

$c^2 = 10^2 + 10^2$

$c^2 = 100 + 100$

$c^2 = 200$

$c = \sqrt{200}$

$c = 14.1 \text { inches}$

$\boxed {\boxed {\text {Answer: The hypotenuse is 14.1 inches}}}$