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Ilya [14]
3 years ago
14

THANKS IF YOU ANSWER,

Mathematics
1 answer:
Yakvenalex [24]3 years ago
4 0
ANSWER: 114ft^2


Area of cabinets = (4*2)+(4*2) = 16ft^2

Area of kitchen = (10*13) = 130ft^2


Subtract area of the cabinets from total area


130ft^2 - 16ft^2 = 114ft^2
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How to do this question plz ​
enyata [817]

Answer:

  x = 10

Step-by-step explanation:

Use the Pythagorean theorem. The sum of the square of the sides is the square of the hypotenuse.

  x² +(√200)² = (√300)²

  x² = 300 -200

  x = √100 = 10

The length of the unknown side is 10 units.

3 0
4 years ago
5/16=n/16 help please
Vsevolod [243]
Both have the same denominator
Remove the denominator
5=n
3 0
3 years ago
Read 2 more answers
12:35 on Sunday.
Neporo4naja [7]

Answer:

See attached

Step-by-step explanation:

Triangle CDE translated 3 units up and reflected over line l into triangle C'D'E'

8 0
3 years ago
The equation of the trend line is y = -0.36x + 12.6.
inysia [295]

Answer:

9.72°F

Step-by-step explanation:

I think that's right :)

4 0
3 years ago
A game is played with a spinner on a circle, like the minute hand on a clock. The circle is marked evenly from 0 to 100, so, for
zheka24 [161]

Answer:

The probability is 1/2

Step-by-step explanation:

The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.

When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.

As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

W = \frac{X - \mu}{\sigma} = \frac{X - 50}{8.333} \simeq N(0,1)

The values of the cummulative distribution of the Standard Normal distribution, lets denote it \phi , are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization

P(X > 50) = P(\frac{X-50}{8.33} > \frac{50-50}{8.33}) = P(W > 0) = \phi(0) = 1/2

Download pdf
8 0
4 years ago
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