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julsineya [31]
3 years ago
9

Solve the differential equation dy/dx=x/49y. Find an implicit solution and put your answer in the following form: = constant. he

lp (formulas) Find the equation of the solution through the point (x,y)=(7,1). help (equations) Find the equation of the solution through the point (x,y)=(0,−3). Your answer should be of the form y=f(x). help (equations)
Mathematics
1 answer:
anygoal [31]3 years ago
4 0

Answer:

The general solution of the differential equation is \frac{49y^{2} }{2}-\frac{x^{2} }{2} = c_{3}

The equation of the solution through the point (x,y)=(7,1) is y=\frac{x}{7}

The equation of the solution through the point (x,y)=(0,-3) is \:y=-\frac{\sqrt{441+x^2}}{7}

Step-by-step explanation:

This differential equation \frac{dy}{dx}=\frac{x}{49y} is a separable first-order differential equation.

We know this because a first order differential equation (ODE) y' =f(x,y) is called a separable equation if the function f(x,y) can be factored into the product of two functions of <em>x</em> and <em>y</em>

f(x,y)=p(x)\cdot h(y) where<em> p(x) </em>and<em> h(y) </em>are continuous functions. And this ODE is equal to \frac{dy}{dx}=x\cdot \frac{1}{49y}

To solve this differential equation we rewrite in this form:

49y\cdot dy=x \cdot dx

And next we integrate both sides

\int\limits {49y} \, dy=\int\limits {x} \, dx

\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1}\\\int\limits {49y} \, dy=\frac{49y^{2} }{2} + c_{1}

\int\limits {x} \, dx=\frac{x^{2} }{2} +c_{2}

So

\int\limits {49y} \, dy=\int\limits {x} \, dx\\\frac{49y^{2} }{2} + c_{1} =\frac{x^{2} }{2} +c_{2}

We can subtract constants c_{3}=c_{2}-c_{1}

\frac{49y^{2} }{2} =\frac{x^{2} }{2} +c_{3}

An explicit solution is any solution that is given in the form y=y(t). That means that the only place that y actually shows up is once on the left side and only raised to the first power.

An implicit solution is any solution of the form  f(x,y)=g(x,y) which means that y and x are mixed (<em>y</em> is not expressed in terms of <em>x</em> only).

The general solution of this differential equation is:

\frac{49y^{2} }{2}-\frac{x^{2} }{2} = c_{3}

  • To find the equation of the solution through the point (x,y)=(7,1)

We find the value of the c_{3} with the help of the point (x,y)=(7,1)

\frac{49*1^2\:}{2}-\frac{7^2\:}{2}\:=\:c_3\\c_3 = 0

Plug this into the general solution and then solve to get an explicit solution.

\frac{49y^2\:}{2}-\frac{x^2\:}{2}\:=\:0

\mathrm{Add\:}\frac{x^2}{2}\mathrm{\:to\:both\:sides}\\\frac{49y^2}{2}-\frac{x^2}{2}+\frac{x^2}{2}=0+\frac{x^2}{2}\\Simplify\\\frac{49y^2}{2}=\frac{x^2}{2}\\\mathrm{Multiply\:both\:sides\:by\:}2\\\frac{2\cdot \:49y^2}{2}=\frac{2x^2}{2}\\Simplify\\9y^2=x^2\\\mathrm{Divide\:both\:sides\:by\:}49\\\frac{49y^2}{49}=\frac{x^2}{49}\\Simplify\\y^2=\frac{x^2}{49}\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

y=\frac{x}{7},\:y=-\frac{x}{7}

We need to check the solutions by applying the initial conditions

With the first solution we get:

y=\frac{x}{7}=\\1=\frac{7}{7}\\1=1\\

With the second solution we get:

\:y=-\frac{x}{7}\\1=-\frac{7}{7}\\1\neq -1

Therefore the equation of the solution through the point (x,y)=(7,1) is y=\frac{x}{7}

  • To find the equation of the solution through the point (x,y)=(0,-3)

We find the value of the c_{3} with the help of the point (x,y)=(0,-3)

\frac{49*-3^2\:}{2}-\frac{0^2\:}{2}\:=\:c_3\\c_3 = \frac{441}{2}

Plug this into the general solution and then solve to get an explicit solution.

\frac{49y^2\:}{2}-\frac{x^2\:}{2}\:=\:\frac{441}{2}

y^2=\frac{441+x^2}{49}\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\y=\frac{\sqrt{441+x^2}}{7},\:y=-\frac{\sqrt{441+x^2}}{7}

We need to check the solutions by applying the initial conditions

With the first solution we get:

y=\frac{\sqrt{441+x^2}}{7}\\-3=\frac{\sqrt{441+0^2}}{7}\\-3\neq 3

With the second solution we get:

y=-\frac{\sqrt{441+x^2}}{7}\\-3=-\frac{\sqrt{441+0^2}}{7}\\-3=-3

Therefore the equation of the solution through the point (x,y)=(0,-3) is \:y=-\frac{\sqrt{441+x^2}}{7}

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