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masha68 [24]
3 years ago
9

Find the area of the compound shapes below !Please help

Mathematics
2 answers:
jenyasd209 [6]3 years ago
4 0

Answer:

86cm

Step-by-step explanation:

zzz [600]3 years ago
4 0

Answer:

Step-by-step explanation:

the first figure is rectangle , so

length = 15cm, breadth = 6cm

therefore area = l * b = 15*6 = 90cm^2

second figure is also a rectangle so,

length = 12+6 =18 cm ( or 9+9) , breadth = 9cm

therefore area = l*b =18*9 = 162cm^2

third figure is a semicircle , so

d = 11+9 = 20 cm  , r = d/2 =20/2 =10cm

area of semicircle = 1/2 * \pi * r^2\\

=1/2*22/7 *10*10

=1100/7 = 157 1/7 cm^2

if you add all the areas then you will get the requires area

hope it helps you

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E Homework: 3.1 Homework
LenKa [72]

The given function is f(z)=3z-8 for the values f(-4), f(2) and f(z-7) respectively -20, -2 and 3z-29 respectively.

The given function is f(z)=3z-8.

We need to find the value of f(-4), f(2), f(z-7).

<h3>What is a function?</h3>

In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.

Now to find f(-4), replace z from -4.

f(-4)=3(-4)-8=-12-8=-20

Now to find f(2), replace z from 2.

f(2)=3(2)-8=6-8=-2

Now to find f(z-7), replace z from z-7.

f(z-7)=3(z-7)-8=3z-21-8=3z-29.

Therefore, the given function is f(z)=3z-8 for the values f(-4), f(2) and f(z-7) respectively -20, -2 and 3z-29 respectively.

To learn more about functions visit:

brainly.com/question/21145944.

#SPJ1

4 0
2 years ago
Find two integers whose sum is 20 and product Is 100​
Neporo4naja [7]

Answer: 10

Step-by-step explanation:

10+10 = 20

10 x 10 = 100

mi would do another but i supposed to be in class :P

5 0
3 years ago
Read 2 more answers
Help please, 30 points reward, i literally have no clue
Brums [2.3K]

The explanation for this is one of my favorite pieces of mathematical reasoning. First, let's thing about distance; what's the shortest distance between two points? <em>A straight line</em>. If we just drew a straight line between A and B, though, we'd be missing a crucial element of the original problem: we also need to pass through a point on the line (the "river"). Here's where the mathemagic comes in.

If we take the point B and <em>reflect it over the line</em>, creating the point B' (see picture 1), we can draw a line straight from A to B' that passes through a point on the line. Notice the symmetry here; the distance from the intersection point to B' is<em> the same as its distance to B</em>. So, if we reflect that segment back up, we'll have a path to B, and because it came from of the line segment AB', we know that it's <em>the shortest possible distance that includes a point on the line</em>.

If we apply this same process to our picture, we see that the line segment AB' crosses the line \ell at the point (1, 1)

6 0
4 years ago
jake spends 2 hours on each homework assignment and he had 3 assignments each day.orlando spend 2 hiurs on each homework assignm
Andrej [43]
Ok so u have to multiply for this one

Work *Jake*:

So he spends 2 hours on each assignment. He has 3 assignments so u have to do :
2*3=6
 
He spend 6 hours a day doing home work so now u have to multiply that by 30:
6*30=180

Work *Orlando*:

So he spends 2 hours on each homework. He has 2 sheets each do so u have to multiply 2 and 2: 
2*2=4

He spends 4 hours a day doing homwork so u  have to multiply it by 30: 
4*30=120


Answer:
 

So Jake spends 130 hours
Orlando spends 120 hours 

Add both together:
120+130=250

They spend 250 hours together on work in 30 days/
4 0
3 years ago
Read 2 more answers
given two terms in a geometric sequence find the 8th term and the recursive formula . a4=-12 and a5=-6
Crazy boy [7]

A geometric sequence is defined by a starting point, a, and a common ratio r

The first term is a, and you get every next term by multiplying the previous one by r.

So, our terms are

\left[\begin{array}{c|c}a_1&a\\a_2&ar\\a_3&ar^2\\a_4&ar^3=-12\\a_5&ar^4=-6\end{array}\right]

We can see that when we pass from a_4 to a_5 the number gets halved (-12 \mapsto -6)

This implies that the common ratio is r = \frac{1}{2}

So, the table becomes

\left[\begin{array}{c|c}a_1&a\\a_2&\frac{1}{2}a\\a_3&\frac{1}{4}a\\a_4&\frac{1}{8}a=-12\\a_5&\frac{1}{16}a=-6\end{array}\right]

So, we can derive the starting point from either a_4 or a_5:

\dfrac{1}{8}a = -12 \iff a = -12\cdot 8 = -96

The sequence is thus

\left[\begin{array}{c|c}a_1&-96\\a_2&-48\\a_3&-24\\a_4&-12\\a_5&-6\\a_6&-3\\\vdots&\vdots\end{array}\right]

And the recursive formula is

a_n = -\dfrac{96}{2^{n-1}}

7 0
4 years ago
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