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Leviafan [203]
3 years ago
11

How do I solve this equation?

Mathematics
2 answers:
Norma-Jean [14]3 years ago
6 0

Answer:

1. move the constant to the right hand side to change its sign.

2.add the numbers.

3. using the absolute value definition rewrite the absolute value equation as two separate equations.

4.slove the equation for X

Step-by-step explanation:

it has two solutions

x=8

x= -9

the answer should be X1= 9, x2 =8

Anika [276]3 years ago
5 0
Hope this helps you

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 1. 14 minus the quotient of 25 and p 2. a number w tripled plus t quadrupled 3. the product of 13 and m plus the product of 2.7
MrMuchimi
1. 14 - 25/p
2. 3w + 4t
3. 13m + 14n
4. 2a . 5b
4 0
3 years ago
How do you figure out 9a divide by a
Nikitich [7]

9/1 and then your answer would be 9 and then add the a so your full answer would be 9a

8 0
3 years ago
Which expression is equivalent?
gregori [183]
The correct option is: Option (C) log_3c - log_{3}9

Explanation:
It is the property of log that if it contains the fraction, it can be expressed as the difference of the log of numerator and the log of denominator.

The general form is:
log( \frac{x}{y} ) = log(x) - log(y)

Hence the correct answer is log_3c - log_{3}9.


8 0
3 years ago
Which of the following expresses the possible number of positive real solutions for the polynomial equation shown below?
sesenic [268]

Answer:  D. Two or zero

Step-by-step explanation: x=-7/6+-1/6√385

There isn't an exact place you could really solve this number, regardless of the way you break it down

5 0
3 years ago
Your co-worker, Amanda, and you are reliving your high school athletic "glory days" during a coffee break. She played basketball
topjm [15]

Answer:

Our score = 0.60, Amanda's score = 0.25

Step-by-step explanation:

For Amanda

μ = 15 , σ = 4

z- score for X = 16 is (From z table)

z = (X - μ)/σ = (16 - 15)/4 = 0.25

For us

μ = 310 , σ = 25

z score for X = 325 (From z table)

z = (325-310)/25 = 0.60

Since our z score is better than Amanda's z score, we can say we did better

4 0
3 years ago
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