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3 years ago

How do I solve this equation?

Mathematics

2 answers:

Norma-Jean [14]3 years ago

6 0

Answer:

1. move the constant to the right hand side to change its sign.

2.add the numbers.

3. using the absolute value definition rewrite the absolute value equation as two separate equations.

4.slove the equation for X

Step-by-step explanation:

it has two solutions

x=8

x= -9

the answer should be X1= 9, x2 =8

Anika [276]3 years ago

5 0

Hope this helps you

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A consumer agency is investigating the blowout pressures of Soap Stone tires. A Soap Stone tire is said to blow out when it sepa

Likurg_2 [28]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: Impact force needed for Sap Stone tires to blow out. (foot-pounds)

n= 29, S= 1358 foot-pound

Soap Stone claims that "The tires will blow out at an average pressure of μ= 26000 foot-pounds with a standard deviation of σ= 1020 foot-pounds.

According to the consumer's complaint, the variability of the blown out forces is greater than the value determined by the company.

Then the parameter of interest is the population variance (or population standard deviation) and to test the consumer's complaint you have to conduct a Chi-Square test for σ².

σ²= (1020)²= 1040400 foot-pounds²

H₀: σ² ≤ 1040400

H₁: σ² > 1040400

α: 0.01

II)

$X^2= \frac{(n-1)S^2}{Sigma^2} ~~X^2_{n-1}$

$X^2_{H_0}= \frac{(n-1)S^2}{Sigma^2}= \frac{(29-1)*(1358)^2}{1040400} = 49.63$

III)

This test is one-tailed to the right and so is the p-value. This distribution has n-1= 29-1= 28 degrees of freedom, so you can calculate the p-value as:

P(X²₂₈≥49.63)= 1 - P(X²₂₈<49.63)= 1 - 0.99289= 0.00711

⇒ The p-value is less than the significance level so the test is significant at 1%. You can conclude that the population variance of the blowout forces is less than 1040400 foot-pounds², at the same level the population standard deviation of the blow out forces is less than 1020 foot-pounds.

99% CI for the variance. Using the X² statistic you can calculate it as:

$[\frac{(n-1)S^2}{X^2_{n-1;1-\alpha /2}} ;\frac{(n-1)S^2}{X^2_{n-1;\alpha /2}} ]$

$X^2_{n-1;\alpha /2}= X^2_{28; 0.005}= 13.121$

$X^2_{n-1;1-\alpha /2}= X^2_{28; 0.995}= 49.588$

$[\frac{28*(1358)^2}{49.588} ;\frac{28*(1358)^2}{13.121} ]$

[1041312.253; 3935415.898] foot-pounds²

I hope this helps!

3 0

3 years ago

Michael borrows money from his uncle, who is charging him simple interest using the formula I = PRT. To figure out what the inte

katen-ka-za [31]

Answer:

Step-by-step explanation:

formula l=PRT

bring PT to right side we get

l/PT = R

R=l/PT

4 0

3 years ago

Kenny has the following data:

lys-0071 [83]

Answer:

Step-by-step explanation:

If range is 6 then the difference between highest and lowest is 6 so 1 + 6 = 7 so b is equal to 7.

7 0

3 years ago

Shoe sizes for men in the United States are known to follow a normal distribution. If you calculated the z-score of a man's shoe

anastassius [24]

Answer:

This value means that his shoe size is 2.9 deviations above the population mean.

And we can find the approximate percentile for his measure like this:

$P(Z$

This correspond to the 99.8 percentile, so then his shoe size is 99.8% above all the shoe sizes.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the shoe size of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,\sigma)$