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3 years ago

If f(x)=3x+7 and g(x)=x^2+4, find f(g(-5))

Mathematics

1 answer:

Charra [1.4K]3 years ago

3 0

Answer:

Step-by-step explanation:

Given f(g(-5)) means that you take the number, -5, and substitute it into g(x) first. The answer provided from that equation will then be the number to be substituted in f(x).

x^2 + 4

-5^2 + 4

25 + 4 [It's positive because -5 x -5 cancels out to make a positive]

29 = g(x), therefore, this is the new number to be substituted for f(x)

3x + 7

3 (29) + 7

87 + 7 [to get 87, multiply 3 by 29]

Therefore, your final answer is 94.

Hope this helps!

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matrenka [14]

Answer:

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3 years ago

A triangle has an area of 54 square inches the height of the triangle is 12 inches what is the length of the base of the triangl

prohojiy [21]

Answer:

The base of the triangle = 9inches

Step-by-step explanation:

Explanation:-

The area of the triangle = $\frac{1}{2} bh$ square units

Given area of the triangle(A) = 54 square inches

Given the height of the triangle (h) = 12 inches

now equating $\frac{1}{2} b h = 54$

$\frac{1}{2} b (12) = 54$

now simplification, we get

6 b = 54

Dividing '6' on both sides, we get

b = 9

The base of the triangle = 9 inches

Conclusion:-

The base of the triangle = 9 inches

6 0

3 years ago

Find the mssing value. I = ? , P = $250.00, r = 4%, t = 2 years

Ber [7]

Answer:

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Step-by-step explanation:

I mean I would say it is 20

4 0

2 years ago

One vertex of a polygon is located at (3, –2). After a rotation, the vertex is located at (2, 3).

motikmotik

yes it is right when the vertex of the first polygon is located on 3 - 2 after rotation the work vertex will be there on (2 , 3) it is right

4 0

2 years ago

Read 2 more answers

Suppose that contamination particle size (in micrometers) canbe modeled as

asambeis [7]

Answer:

c) 2

d) 0.96

Step-by-step explanation:

We are given the following in the question:

$f(x) = 2x^{-3}, x > 1\\~~~~~~~= 0, x \leq 1$

a) probability density function.

$\displaystyle\int^{\infty}_{\infty}f(x) dx = 1\\\\\displaystyle\int^{\infty}_{-\infty}2x^{-3}dx = 1\\\\\displaystyle\int^{\infty}_{1}2x^{-3}dx\\\\\Rightarrow \big[-x^{-2}\big]^{\infty}_1\\\\\Rightarrow -(0-1) = 1$

Thus, it is a probability density function.

b) cumulative distribution function.

$P(X$

c) mean of the distribution

$\mu = \displaystyle\int^{\infty}_{-\infty}xf(x) dx\\\\\mu = \int^{\infty}_12x^{-2}dx\\\\\mu = (-\frac{2}{x})^{\infty}_{1}\\\\\mu = 2$

d) probability that the size of random particle will be less than 5 micrometers

$P(X$

4 0

2 years ago