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svet-max [94.6K]
3 years ago
9

Add the polynomials. Be sure to write your answer in standard form. (−4x3−5x+2)+(4x3+10)

Mathematics
1 answer:
Marat540 [252]3 years ago
4 0
-5x+12 is the answer
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Find the minimum/maximum of y=2x^2+12x-22
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Answer:

The minimum value of this function is -40.

Step-by-step explanation:

Recall that the minimum of a quadratic whose graph is a parabola that opens up, as this one does, is the vertex of the graph.  The x-coordinate of the vertex is given by x = -b / (2a), where a is the coefficient of the x^2 term and b is that of the x term.

Here, x = -12 / (2*2), or x = -12/4, or x = -3.

Find the y-value at this x-value:  f(-3) = 2(-3)^2 + 12(-3) - 22, or

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The vertex is at (-3, -40).  The minimum value of this function is -40.

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1

Step-by-step explanation:

GCF(18, a, 20ab) = 1

18 and <em>a</em> do not necessarily have any factor in common, so their GCF is 1. Adding more terms to the list will not increase the GCF beyond that value.

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The answer is 4/18

——
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