Answer:
Step-by-step explanation:
Let the base camp is point A and boats' locations after two hours are points B and C.
By connecting the three points together we get a triangle ABC with sides:
- AB = 50*2 = 100 km
- AC = 70*2 = 140 km
The angle between AB and AC is:
- 60 + 50 = 110 degrees (opposite directions from south)
We are looking for the distance BC, which can be found by using the law of cosines:
- BC² = AB² + AC² - 2AB*AC*cos ∠BAC
- BC² = 100² + 140² - 2*100*140*cos 110°
- BC² = 39176.56 (rounded)
- BC = √39176.56 = 197.93 km (rounded)
The distance between the boats is 197.93 km.
Answer:
3/5 or
0.6
Step-by-step explanation:
You could change these fractions to decimals, but you may not be convinced that the answer you get is the same as just using fractions. I'll start by using fractions.
x - 2/5 = 1/5 Add 2/5 to both sides
x - 2/5 + 2/5 = 1/5 + 2/5 The left side cancels to 0.
x = 1/5 + 2/5 The denominators (bottom the fraction) are the same. Just add the tops.
x = (1 + 2)/5
x = 3/5
=======================
If you use your calculator to find 2/5 and 1/5, you can get the same answer as 3/5
2
÷
5
=
0.4
By the same method, 1/5 = 0.2
Substitute into the original equation
x - 0.4 = 0.2 Add 0.4 to both sides
x - 0.4 +0.4 = 0.2 + 0.4 The left side reduces just to x
x = 0.2 +0.4
x = 0.6
If you let your calculator do the work, like this
3
÷
5
=
0.6
The answers are the same.
What was his average speed rate on his way to Seattle?
Ans: 62mph
On which part of his trip did he average a faster speed rate?
Ans: When he returned home.
X would equal 9. Subtract 18 from both sides then divide by two to get 9 as X