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3 years ago

For the following scenarios, determine whether or not they represent paired samples.

Mathematics

1 answer:

Aneli [31]3 years ago

8 0

Answer:

A = Not a paired sample

B = paired sample

C = Not a paired sample

Step-by-step explanation:

Paired samples also commonly referred to as dependent samples are often characterized by having to different data points which are taken at different times, location and so on. Such that each pair of data points or observation can be matched based on the basis of the subject or sample name usually for the sake of analysing if any statistical difference exists between the occurrence of each observation.

For the instances given above ;

a.) this isn't a paired sample, because Professor Quick and Professor Quacks students are different, hence each student has only one reading and as such a match of the two test scores cannot be made on the basis of student name or identity. Hence, it is not a paired sample

B.) This is a paired sample, two different readings are available for each students ; one at the beginning, the other at the end. Hence, it is a paired sample

C.) This is not a paired sample, because the subjects used to obtain the weight of 10 year old in 1994 aren't the same samples used in 2009

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The answer is 6.

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You should see the denominator of the function in this case.
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3 years ago

Kody made a deposit into an account that earns 4% annual compound interest. After 24 months, the value of his account was $2,163

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Kody made an initial deposit of $2,000

Step-by-step explanation:

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3 years ago

You want to buy new kitchen appliances 2 years from now, and you plan to save $8,200 per year, beginning one year from today. yo

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3 years ago

3. For the polynomial: ()=−2(+19)3(−14)(+3)2, do the following:A. Create a table of values that have the x-intercepts of p(x) in

Pepsi [2]

Part A. We are given the following polynomial:

$\mleft(\mright)=-2\mleft(+19\mright)^3\mleft(-14\mright)\mleft(+3\mright)^2$

This is a polynomial of the form:

$p=k(x-a)^b(x-c)^d\ldots(x-e)^f$

The x-intercepts are the numbers that make the polynomial zero, that is:

$\begin{gathered} p=0 \\ (x-a)^b(x-c)^d\ldots(x-e)^f=0 \end{gathered}$

The values of x are then found by setting each factor to zero:

$\begin{gathered} (x-a)=0 \\ (x-c)=0 \\ \text{.} \\ \text{.} \\ (x-e)=0 \end{gathered}$

Therefore, this values are:

$\begin{gathered} x=a \\ x=c \\ \text{.} \\ \text{.} \\ x=e \end{gathered}$

In this case, the x-intercepts are:

$\begin{gathered} x=-19 \\ x=14 \\ x=-3 \end{gathered}$

The multiplicity are the exponents of the factor where we got the x-intercept, therefore, the multiplicities are:

Part B. The degree of a polynomial is the sum of its multiplicities, therefore, the degree in this case is:

$\begin{gathered} n=3+1+2 \\ n=6 \end{gathered}$

To determine the end behavior of the polynomial we need to know the sign of the leading coefficient that is, the sign of the coefficient of the term with the highest power. In this case, the leading coefficient is -2, since the degree of the polynomial is an even number this means that both ends are down. If the leading coefficient were a positive number then both ends would go up. In the case that the leading coefficient was positive and the degree and odd number then the left end would be down and the right end would be up, and if the leading coefficient were a negative number and the degree an odd number then the left end would be up and the right end would be down.

Part C. A sketch of the graph is the following:

If the multiplicity is an odd number the graph will cross the x-axis at that x-intercept and if the multiplicity is an even number it will tangent to the x-axis at that x-intercept.

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2 years ago