All categories

3 years ago

Round the nearest whole number 3 3/8

Mathematics

2 answers:

Maurinko [17]3 years ago

6 0

3 /8 = .375
3 + .375 = 3.375
3.375 rounded to nearest whole number is 3

adoni [48]3 years ago

3 0

It would be 3.375 before rounding so if you round it to the nearest whole number it would be 3 since be hind the first 3 is under 5

You might be interested in

What is the surface area of this right prism?

Amiraneli [1.4K]

Answer:

Since the 'base' and 'top' of any prism have the same shape, the surface area can be found by

surface area of prism = 2 * area of base + perimeter of base * H

So for the rectangular prism in your example..

surface area = 2LW + 2(L+W)H

= 2 * 7 * 4 + 2*(7+4)*5

= 56 + 2 * 11 * 5

= 56 +110

= 166 sq cm

Hope this helps

5 0

2 years ago

What are the vertex, axis of symmetry, domain and range of the function:

DiKsa [7]

Y=(-x*x)-4x+3
y=-(x^2+4x-3)
4+y=-(x^2+4x+4)+3
y+4=-(x-2)^2.) +3
-4. -4
y=-((x-2)^2)-1

Answers:
Vertex: (2,-1)
AOS:x = 2
Domain: All Real Numbers
Range:[-1,Infinity)

3 0

2 years ago

allowing 20% discount on the marked price of a watch the value of the watch will be Rs 6328 when a vat 13%is added ,find the fin

Ahat [919]

Step-by-step explanation:

Let the marked price of a watch be =₹x

∴ Discount price = x- 20% of x

= x - 0.2x

=0.8x

Amount of VAT = 13% of 0.8x

0.13 x 0.8x

0.104x

Now,

Selling price = 0.8x + 0.104x

∴6328 = 0.904x

x = 0.904 / 6328

x=0.00014285714

7 0

2 years ago

Can someone please help me with this ?

Galina-37 [17]

Answer:

Step-by-step explanation:

<h3>Haiaisiisisisisiisjsjsjsjjjxjxixijsbsbs</h3>

3 0

3 years ago

1) If the alpha level is changed from α = .05 to α = .01, what happens to boundaries for the critical region?

Alexxandr [17]

Answer:

1) a. Move farther into the tails

2) a. Decreases

Step-by-step explanation:

Hello!

Let's say for example that you are making a confidence interval for the mean, using the Z-distribution:

X[bar] ± $Z_{1-\alpha /2}$ * $\frac{Sigma}{\sqrt{n} }$

Leaving all other terms constant, this are the Z-values for three different confidence levels:

90% $Z_{0.95}= 1.648$

95% $Z_{0.975}= 1.965$

99% $Z_{0.995}= 2.586$

Semiamplitude of the interval is

d= $Z_{1-\alpha /2}$ * $\frac{Sigma}{\sqrt{n} }$

Then if you increase the confidence level, the value of Z increases and so does the semiamplitude and amplitude of the interval:

↑d= ↑ $Z_{1-\alpha /2}$ * $\frac{Sigma}{\sqrt{n} }$

They have a direct relationship.

So if you change α: 0.05 to α: 0.01, then the confidence level 1-α increases from 0.95 to 0.99, and the boundaries move farther into the tails.

The significance level of a hypothesis test is the probability of committing a Type I error.

If you decrease the level from 5% to 1%, then logically, the probability decreases.

I hope this helps!

5 0

3 years ago