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weqwewe [10]
3 years ago
10

If you slice a rectangular pyramid parallel to its base, name the shape of the cross section made in the pyramid.

Mathematics
2 answers:
viva [34]3 years ago
8 0

Answer:

If you slice a rectangular pyramid parallel to the base, you get a smaller rectangle as the cross-section.

lidiya [134]3 years ago
8 0

Answer:

A rectangle

Step-by-step explanation:

A cross section parallel to the base of a pyramid will be a similar shape as the base of the pyramid.  In this case, a rectangle.

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A music store sold a total of 27 used trumpets and clarinets in one month. Trumpets cost $149 and clarinets cost $99. If total s
vodomira [7]
Answer: 16

Solution:

1) Use letters to identify the variables:

Number of trumpets: t
Number of clarinets: c

2) Translate each statement into algebraic (mathematical) language.

2.1) Sold a total of 27 used trumpets and clarinets

=> t + c = 27

2.2) Trumpets cost $149 and clarinets cost $99

Total cost of the trumpets: 149t
Total cost of clarinets: 99c

Total cost = 149t + 99c

2.3) Total sales were $3223

=> 149t + 99c = 3223.

3) State the system of equations:

Equation (1) t + c = 27
Equation (2) 149t + 99c = 3223

4) Solve the system of equations:

4.1) Multiply equation 1 by 149:

=> 149t + 149c = 4023

4.2) Subtract the equation (2) from the equation obtained in 4.1

=> 149c - 99c = 4023 - 3223

=> 50c = 800

=> c = 800 / 50 = 16

5) Verify the solution:

From equation (1) t = 27 - 16 = 11

Total cost = 149*11 + 99*16 = 3223

Now you have a verified answer: they sold 16 clarinets
7 0
3 years ago
Brainliest if correct
dybincka [34]

Answer:

-2

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Work out length of side b<br>give your answer to 1 decimal place<br><br>plzzzz hhheellpp​
Vedmedyk [2.9K]

√b = 17.17 - 12.12

√b= 289 - 144

√b= 145

b= √145

3 0
2 years ago
Read 2 more answers
Solve 3x2 + 4x = −5.
Alla [95]
Move the -5 over by adding 5 to both sides
3x^2+4x+5=0
must use quadratic formula

for an equation in the form
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

a=3
b=4
c=5

x=\frac{-4+/- \sqrt{4^2-4(3)(5)} }{2(3)}
x=\frac{-4+/- \sqrt{16-60} }{6}
x=\frac{-4+/- \sqrt{-44} }{6}
x=\frac{-4+/- 2\sqrt{-11} }{6}
remember that√-1=i
x=\frac{-4+/- 2i\sqrt{-11} }{6}
x=\frac{-2+/- i\sqrt{-11} }{3}

x=\frac{-2+ i\sqrt{-11} }{3} or x=\frac{-2- i\sqrt{-11} }{3}


4 0
3 years ago
Hurry please!!! Fast response
AlladinOne [14]

Answer:

A.

SA= \frac{2}{3} \pi rl+16 \pi r^2

Step-by-step explanation:

Surface area of the original cone

SA= \pi r l + \pi r^2... (1)

When, radius is quadrupled and slant height is reduced to one sixth

i. e. \: \:r = 4r\: \: \&\:\: l= \frac{1}{6}l

Plug the above values of r and l in equation (1), new surface area becomes:

SA= \pi (4r)\times \frac{1}{6} l+ \pi (4r)^2

SA= \frac{4}{6} \pi rl+16 \pi r^2

\huge \purple {\boxed {SA= \frac{2}{3} \pi rl+16 \pi r^2}}

8 0
2 years ago
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