Answer:
. a reference point is required to determine whether or not an object moves
Explanation:
Answer:
b. CI (1255 kJ/mol), Ge (784 kJ/mol), and K (418 kJ-mol)
Explanation:
In general, the first ionization energy for a given period increases as we go from left to right in the periodic table (there are some exeptions as with every rule), and the first ionization energy decreases a we go down in the periodic table. The reason for this are:
1. As we move from left to right in a group, the effective nuclear charge increases which makes it harder to remove the electron.
2. As we increase the period in going top to bottom in the periodic table we are adding another shell farther away from the nucleus, making it easier to remove the electron.
Given the three values for the first ionization energy in kJ/mol : 418, 784 and 1255, we expect the highest value to correspond to Cl which belongs to period 3 (K and Ge belong to period 4).
Now comparing K and Ge which belong to period 4, Ge will have a higher effective nuclear charge than K .
So the match will be Cl (1255 kJ/mol), Ge (784) and K(418)
Correct answer is b.
Note: there could be some confusion since the value of 784 was misplaced in the question statement, but we can deduce that in this question we are asked to match the values for the atoms.
Answer:
A concentrated acid is an acid which is in either pure form or has a high concentration. Laboratory type sulfuric acid (about 98% by weight) is a concentrated (and strong) acid. A dilute acid is that in which the concentration of the water mixed in the acid is higher than the concentration of the acid itself.
Explanation:
Concentrated acid - Those acids which are pure or have very high concentration in water are called as concentrated acids. For example concentrated Hydrochloric acid (HCl) and concentrated Sulphuric acid are examples of concentrated acids.
The final temperature of the sample, in degrees Celsius is 36.6 °C
<h3>Heat capacity of a substance</h3>
From the question, we are to determine the final temperature of the sample
From the formula for heat capacity, we have that
Q = mcΔT
Where Q is the heat energy
m is the mass
c is the specific heat capacity of the subtance
ΔT is the change in temperature ()
From the given information
m = 687.6 g
Q = 8284.4 J
= 23.1 °C
Putting the parameters into the equation, we get
NOTE: Specific heat capacity of aluminum = 0.89 J/ g °C
Then,
Hence, the final temperature of the sample, in degrees Celsius is 36.6 °C
Learn more on Heat capacity of a substance here: brainly.com/question/13439286
Answer:
The ratios of mole O2 to mole KClO3 are: 3/2, 1.5/1,1/2
Explanation:
The 3 possible equation of reaction for the decomposition of KClO3 are:
2KClO3 ==> 2KCl + 3O2
KClO3 ==> KCl + 1.5O2
2KClO3 ==> 2KClO2 + O2
When potassium chlorate (KClO3) is heated in the presence of manganese dioxide catalyst, it decomposes to form potassium chloride and oxygen gas.