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Evgesh-ka [11]
2 years ago
6

If the temperature on 244 mL of a gas is changed to 488 mL and 6 atm, at constant

Chemistry
1 answer:
Fittoniya [83]2 years ago
6 0

Answer:

<h2>12 atm</h2>

Explanation:

To find the initial pressure we use the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the initial pressure

P_1 =  \frac{P_2V_2}{V_1}  \\

From the question we have

P_1 =  \frac{488 \times 6}{244}  =  \frac{2928}{244}  \\

We have the final answer as

<h3>12 atm</h3>

Hope this helps you

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Solving part-1 only

#1

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#2

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Let's find how?

\\ \tt\Rrightarrow x+1+4(-2)=0

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\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}

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