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scoundrel [369]
3 years ago
12

A number k is greater than 3. Which of thefollowing is true about k over 3 ?​

Mathematics
1 answer:
FrozenT [24]3 years ago
4 0

Well, there is nothing following, but if there is anything about K equal to or greater 4, or K being>2 than thats it.

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What is the true solution to 2 In eln 5x – 2 In 15?
babunello [35]

Answer:

x = 49.84

Step-by-step explanation:

We are given an equation of unknown x and we have to solve the equation for x.

2\ln(e\ln5x)-2\ln15 =0

⇒ ln(e\ln5x) = \ln15

⇒ \ln e + \ln \ln 5x = \ln 15 {Since we know that  ln AB =ln A + ln B}

⇒ \ln \ln 5x = \ln 15 -\ln e

⇒ \ln \ln 5x=\ln \frac{15}{e} {Since we know that ln A/B = ln A - ln B}

⇒ \ln 5x = \frac{15}{e}

⇒ 5x = e^{\frac{15}{e} }

⇒ x = \frac{1}{5} e^{\frac{15}{e} }{Converting logarithm to exponent form}

⇒ x = 49.84 (Approximate) (Answer)

6 0
4 years ago
Help im diening please
Alina [70]

Answer:

y = x + 3

Step-by-step explanation:

To know which of the equations represent the relationship between x and y, you need to substitute the x and y values into the equation. If when the equation is solved, the left-hand and right-hand side of the equation equal each other and hence the equation is true, then the equation must be correct in expressing the relationship between the x and y values. If not, then it is not correct.

As this question is only dealing with linear equations, we know that the gradient of the line is constant and hence the rate of change in x and y values is constant. Therefore, we can choose to substitute any of the given combinations of x and y values into the equation to obtain the correct equation. As it is easier to use smaller numbers for smaller calculations, we'll use the first combination of x = 1 and y = 4 .

<em>Equation</em><em> </em><em>No</em><em>.</em><em> </em><em>1</em><em> </em><em>:</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>3x</em><em> </em><em>+</em><em> </em><em>1</em><em> </em><em>where</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em> </em><em>,</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>4</em><em> </em><em>and</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>,</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>5</em>

( 4 ) = 3 ( 1 ) + 1

4 = 4

However, as this equation has a constant not equal to 1 in front of the x variable and hence a different gradient to the other equations, we will substitute the second combination of x and y values.

( 5 ) = 3 ( 2 ) + 1

5 = 6

Therefore, equation is false / incorrect.

<em>Equation</em><em> </em><em>No</em><em>.</em><em> </em><em>2</em><em> </em><em>:</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>x</em><em> </em><em>+</em><em> </em><em>1</em><em> </em><em>where</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em> </em><em>,</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>4</em>

( 4 ) = ( 1 ) + 1

4 = 2

Therefore, equation is false / incorrect.

<em>Equation</em><em> </em><em>No</em><em>.</em><em> </em><em>3</em><em> </em><em>:</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>x</em><em> </em><em>+</em><em> </em><em>3</em><em> </em><em>where</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em> </em><em>,</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>4</em>

( 4 ) = ( 1 ) + 3

4 = 4

Therefore, equation is true / correct.

<em>Equation</em><em> </em><em>No</em><em>.</em><em> </em><em>4</em><em> </em><em>:</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>3</em><em> </em><em>where</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em> </em><em>,</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>4</em>

( 4 ) = ( 1 ) - 3

4 = - 2

Therefore, equation is false / incorrect.

8 0
3 years ago
What’s the radius of a circle with the circumference of 37.68 feet
Lina20 [59]

Answer:

r≈6ft

Step-by-step explanation:

Using the formula

C=2πr

Solving forr

r=C

2π=37.68

2·π≈5.99696ft

pls mark as brainliest

7 0
3 years ago
What is the volume of a sphere with a diameter of 2.8 cm, rounded to the nearest tenth of a cubic centimeter?
djverab [1.8K]

Answer:

11.5 cm^3

Step-by-step explanation:

The volume of a sphere is (4/3)(pi)(r^3). To find the radius, divide the diameter of 2.8 to get 1.4. Then plug it in to get 11.49. 11.49 rounded to the nearest tenth is 11.5 cm^3.

7 0
3 years ago
Could someone check if this graph is correct or not please.
torisob [31]

Answer:

It looks right to me good job

7 0
3 years ago
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