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kirill115 [55]
3 years ago
15

Find the derivative of f(x) =( -7/x) at x = -3. pls help !!

Mathematics
1 answer:
jeka57 [31]3 years ago
5 0

Answer:

\displaystyle f'(-3) = \frac{7}{9}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative of a constant is a 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]:                                                                               \displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle f(x) = \frac{-7}{x}<u />

<u />\displaystyle x = -3<u />

<u />

<u>Step 2: Differentiate</u>

  1. Quotient Rule:                                                                                                   \displaystyle f'(x) = \frac{\frac{d}{dx}[7]x - \frac{d}{dx}[x](-7)}{x^2}
  2. Basic Power Rule:                                                                                             \displaystyle f'(x) = \frac{(0)x - x^{1 - 1}(-7)}{x^2}
  3. Simplify:                                                                                                             \displaystyle f'(x) = \frac{(0)x - x^0(-7)}{x^2}
  4. Simplify:                                                                                                             \displaystyle f'(x) = \frac{(0)x - 1(-7)}{x^2}
  5. Multiply:                                                                                                             \displaystyle f'(x) = \frac{0 + 7}{x^2}
  6. Add:                                                                                                                   \displaystyle f'(x) = \frac{7}{x^2}

<u>Step 3: Solve</u>

  1. Substitute in <em>x</em> [Derivative]:                                                                              \displaystyle f'(-3) = \frac{7}{(-3)^2}
  2. Evaluate exponents:                                                                                         \displaystyle f'(-3) = \frac{7}{9}

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

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