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siniylev [52]
3 years ago
11

A teacher bought 7 packs of dominoes for a math game. Each pack had 55 dominoes. The teacher already had 118 dominoes to use in

the game. Estimate how many dominoes the teacher had for the game.
Mathematics
1 answer:
Mamont248 [21]3 years ago
8 0

Answer:

the teacher had 503 dominoes for the game.

Step-by-step explanation:

In order to find the answer, first you have to find the amount of dominoes the teacher purchased by multiplying the number of packs for the number of dominoes in each pack:

7*55=385

Now, since the stament indicates that the teacher already had 118 dominoes to use in the game, you have to add this amount to the number of dominoes that were purchased:

385+118=503

According to this, the answer is that the teacher had 503 dominoes for the game.

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can someone help me with this problem, please? Solve the triangle. Round decimal answers to the nearest tenth.
Novay_Z [31]

Answer:

A is about 37.6 degrees

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Step-by-step explanation:

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3 years ago
Given that sin(90 -5thetha) = Cos(180 - 0),<br>Find the value of theta​
Dmitry [639]

Answer:

θ = 54 - π/10 - (2 π n_1)/5 for n_1 element Z

or θ = -18 - π/10 - (2 π n_2)/5 for n_2 element Z

Step-by-step explanation:

Solve for θ:

sin(90 - 5 θ) = cos(180)

Hint: | Express the right hand side in terms of sine.

Rewrite the right hand side using cos(θ) = sin(θ + π/2):

sin(90 - 5 θ) = sin(π/2 + 180)

Hint: | Eliminate the sine from the left hand side.

Take the inverse sine of both sides:

90 - 5 θ = -180 + π/2 + 2 π n_1 for n_1 element Z

or 90 - 5 θ = 180 + π/2 + 2 π n_2 for n_2 element Z

Hint: | Look at the first equation: Isolate terms with θ to the left hand side.

Subtract 90 from both sides:

-5 θ = -270 + π/2 + 2 π n_1 for n_1 element Z

or 90 - 5 θ = 180 + π/2 + 2 π n_2 for n_2 element Z

Hint: | Solve for θ.

Divide both sides by -5:

θ = 54 - π/10 - (2 π n_1)/5 for n_1 element Z

or 90 - 5 θ = 180 + π/2 + 2 π n_2 for n_2 element Z

Hint: | Look at the second equation: Isolate terms with θ to the left hand side.

Subtract 90 from both sides:

θ = 54 - π/10 - (2 π n_1)/5 for n_1 element Z

or -5 θ = 90 + π/2 + 2 π n_2 for n_2 element Z

Hint: | Solve for θ.

Divide both sides by -5:

Answer: θ = 54 - π/10 - (2 π n_1)/5 for n_1 element Z

or θ = -18 - π/10 - (2 π n_2)/5 for n_2 element Z

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3 years ago
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