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Firdavs [7]
3 years ago
5

Solve the equation for b 5= 3/2 (3) + b

Mathematics
1 answer:
kaheart [24]3 years ago
3 0

Answer:

The answer is b = 1/2

Step-by-step explanation:

1) Use this rule: a/b × c = ac/b.

5 =  \frac{3 \times 3}{2}  + b

2) Simplify 3 × 3 to 9.

5 =  \frac{9}{2}  + b

3) Subtract 9/2 from both sides.

5 -  \frac{9}{2}  = b

4) Simplify 5 - 9/2 to 1/2.

\frac{1}{2}  = b

5) Switch sides.

b =  \frac{1}{2}

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>b</u><u> </u><u>=</u><u> </u><u>1</u><u>/</u><u>2</u><u>.</u>

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Prove that the points P(-1,1) ,Q(2,3) and R(2,1) are the vertices of a salence triangle. Plz ans fast.​
guajiro [1.7K]

Step-by-step explanation:

P(-1,1), Q(2,3), R(2,1)

Let P(-1,1)be x1and y1

Q(2,3)be x2 and y2

therefore, by distance formula

d(PQ)= root (x2-x1)^2+(y2-y1)^2

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d( PQ) = root 13.........(1)

Now find distance QR and PR then prove that the three sides are not equal and therefore it is a scalene triangle

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What is an equation in standard form of an ellipse centered at the origin with vertex (3, 0) and co-vertex (0, - 6) ?
Leto [7]

An equation in standard form of the given ellipse is; x²/9 + y²/36 = 1

<h3>How to find the equation of an ellipse?</h3>

We know that the general standard form of equation of an Ellipse is;

x²/a² + y²/b² = 1

where;

a is the vertex and b is the co-vertex.

Thus, the equation here is;

x²/3² + y²/(-6)² = 1

⇒ x²/9 + y²/36 = 1

Read more about Ellipse Equation at; brainly.com/question/10259559

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