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Luba_88 [7]
3 years ago
9

There are three numbers for the combination to the store’s safe. The first number is 17. The other two numbers can be multiplied

together to give a product of 28. What are all of the possibilities for the other two numbers? Write your answers as multiplication equations, and then write all of the possible combinations to the safe.
Mathematics
1 answer:
dlinn [17]3 years ago
7 0

Answer:

Step-by-step explanation:

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Step-by-step explanation:

V = 1/2 a x c x h

1/2 * 7*12*18 = 756 yd ^3

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Find the length of the hypotenuse. Round your<br> answer to the nearest hundredth.
sergij07 [2.7K]

Answer:

8.06

Step-by-step explanation:

a^2 + b^2 = c^2

4^2 + 7^2 = c^2

16 +  49 = c^2

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8.06

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If a random sample of size nequals=6 is taken from a​ population, what is required in order to say that the sampling distributio
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Answer:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

Step-by-step explanation:

For this case we have that the sample size is n =6

The sample man is defined as :

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And we want a normal distribution for the sample mean

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

So for this case we need to satisfy the following condition:

X_i \sim N(\mu , \sigma), i=1,2,...,n

Because if we find the parameters we got:

E(\bar X) =\frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n}=\mu

Var(\bar X)= \frac{1}{n^2} \sum_{i=1}^n Var(X_i) = \frac{n\sigma^2}{n^2}= \frac{\sigma^2}{n}

And the deviation would be:

Sd (\bar X) = \frac{\sigma}{\sqrt{n}}

And we satisfy the condition:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

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Read The Question On The Following PNG
ipn [44]
A. Will most likely be the answer I might be wrong.
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3 years ago
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