Answer:
20
Step-by-step explanation:
Use <u>PEMDAS</u>
P = parenthesis
E = Exponents
M = Multiplication*
D = Division*
A = Addition**
S = Subtraction**
*either can come first, it just depends which comes first in the equation.
**either can come first, it just depends which comes first in the equation.
<em>Step 1 : Write equation</em> 4( 9 × 2 ) ÷ ( 4 -1 ) - 4
<em>Step 2: Solve in parenthesis </em>4(18) ÷ (3) - 4
<em>Step 3: Solve multiplication </em> 72 ÷ 3 - 4
<em>Step 4: Solve division </em>24 - 4
<em>Step 5 : Solve subtraction</em> 20
D) a.b > 0 is the wrong answer
yes, there are infinitety many polynomial that have exactly one real root just like your example, to determine the real root first let the real root is a, and the complex roots are b±ic the polynomial satisfy
-9x³ + 19x² + 17 = -(x - a)(x - b - ic)(x - b + ic)
9x³ - 19x² - 17 = (x - a)(x - b - ic)(x - b + ic)
Answer: i will just let me know what
Step-by-step explanation:
Answer:
The answer is
n=5 3/5
Step-by-step explanation:
first collect the like terms:
2-1/2n=3n+16
then...
3n-1/2=16-2
==2 1/2n = 14
===n=5 3/5
