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1 year ago

Solve for x in the given equation: ax - b = c

Mathematics

1 answer:

lord [1]1 year ago

5 0

An equation is formed of two equal expressions. The value of x is the equation ax-b=c is (c+b)/(a).

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The solution of x in the given equation can be written as,

$ax - b = c\\\\ax = c+b\\\\x = \dfrac{c+b}{a}$

Hence, the value of x is the equation ax-b=c is (c+b)/(a).

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2. Los valores de x=+19 son solución de la ecuación:

Irina18 [472]

Answer:

Creo que la respuesta es A

Step-by-step explanation:

porque u lo divide todo y es el primero porque es igual a un número entero

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2 years ago

I’m confused with this question.

zhenek [66]

Answer:

I'm pretty sure SSS since it's all sides that are equal to each other.

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2 years ago

Find the mode for the<br> following data set {1,3,5,7,9]<br><br> PLS HELP

kvasek [131]

Answer: There is no mode.

Step-by-step explanation:

The mode is the number in a data set that occurs most frequently. Count how many times each number occurs in the data set. The mode is the number with the highest tally. It's ok if there is more than one mode. And if all numbers occur the same number of times there is no mode.

Hope this helps!

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3 years ago

Explain why each of the following integrals is improper. (a) 4 x x − 3 dx 3 Since the integral has an infinite interval of integ

erma4kov [3.2K]

Answer:

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

Since the integral has an infinite interval of integration, it is a Type 1 improper integral

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

Step-by-step explanation:

Considering a

$\int\limits^4_3 {\frac{x}{x- 3} } \, dx$

Looking at this we that at x = 3 this integral will be infinitely discontinuous

Considering b

$\int\limits^{\infty}_0 {\frac{1}{1 + x^3} } \, dx$

Looking at this integral we see that the interval is between $0 \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering c

$\int\limits^{\infty}_{- \infty} {x^2 e^{-x^2}} \, dx$

Looking at this integral we see that the interval is between $-\infty \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering d

$\int\limits^{\frac{\pi}{4} }_0 {cot (x)} \, dx$

Looking at the integral we see that at x = 0 cot (0) will be infinity hence the integral has an infinite discontinuity , so it is a Type 2 improper integral

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2 years ago

Simplify this expression: (-2 - 8x) + (-4x - 10)

nevsk [136]

Answer:

The simplified form of expression<u> </u>(-2 - 8x) + (-4x - 10) is

-12(x + 1)

Step-by-step explanation:

It is given an expression (-2 - 8x) + (-4x - 10)

<u>To find the simplified expression of (-2 - 8x) + (-4x - 10)</u>

Let expression is given by

(-2 - 8x) + (-4x - 10) = -2 - 8x -4x -10

= -2 -10 -4x -8x

= -12 -12x

-12(x + 1) (since -12 is common in both terms)

Therefore simplified form is -12(x + 1)

5 0

2 years ago

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