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ale4655 [162]
2 years ago
12

Write a short para based on how the pandemic has affected travelling.

Mathematics
2 answers:
kozerog [31]2 years ago
5 0

Answer:

Unlike many of history’s great tragedies, the coronavirus pandemic never stunned us with one catastrophic event. Instead, the deadly problem quietly snaked its way around the world, devastating millions as it grew into a global health crisis since it first surfaced in November.

Our realities shifted slowly at first, and before we knew it, the coronavirus took over completely.

As we closed borders, canceled events and self-quarantined at home on a mass scale, the travel industry, as well as most other sectors, began to nosedive. The collective effort to save lives meant economic catastrophe for an industry that profits from people leaving their houses.

The wound inflicted by the pandemic on the travel industry is deep, and it hasn’t stopped bleeding yet.

In a May 20 call with analysts, Royal Caribbean Cruises chief executive Richard Fain recalled how drastically travel changed after the 9/11 terrorist attacks — and how the “new normal” eventually just became normal. He expects to see a similar phenomenon in the post-coronavirus world.

NikAS [45]2 years ago
4 0

sorry it didnt let me send it so i took a lictire of it stay safe out there in the world wherever you are to let you know god is with you all the time if your in fear pray to him and he will take the fear away from you. anyways, stay safe and love you all!❤

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Lamaj is rides his bike over a piece of gum and continues riding his bike at a constant rate time = 1.25 seconds the game is at
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Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. At time = 1.25 seconds, the gum is at a maximum height above the ground and 1 second later the gum is on the ground again.

a. If the diameter of the wheel is 68 cm, write an equation that models the height of the gum in centimeters above the ground at any time, t, in seconds.

b. What is the height of the gum when Lamaj gets to the end of the block at t = 15.6 seconds?

c. When are the first and second times the gum reaches a height of 12 cm?

Answer:

Step-by-step explanation:

a)

We are being told that:

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. This keeps the wheel of his bike in Simple Harmonic Motion and the Trigonometric equation  that models the height of the gum in centimeters above the ground at any time, t, in seconds.  can be written as:

\mathbf {y = 34cos (\pi (t-1.25))+34}

where;

y =  is the height of the gum at a given time (t) seconds

34 = amplitude of the motion

the amplitude of the motion was obtained by finding the middle between the highest and lowest point on the cosine graph.

\mathbf{ \pi} = the period of the graph

1.25 = maximum vertical height stretched by 1.25 m  to the horizontal

b) From the equation derived above;

if we replace t with 1.56 seconds ; we can determine the height of the gum when Lamaj gets to the end of the block .

So;

\mathbf {y = 34cos (\pi (15.6-1.25))+34}

\mathbf {y = 34cos (\pi (14.35))+34}

\mathbf {y = 34cos (45.08)+34}

\mathbf{y = 58.01}

Thus, the  gum is at 58.01 cm from the ground at  t = 15.6 seconds.

c)

When are the first and second times the gum reaches a height of 12 cm

This indicates the position of y; so y = 12 cm

From the same equation from (a); we have :

\mathbf {y = 34 cos(\pi (t-1.25))+34}

\mathbf{12 = 34 cos ( \pi(t-1.25))+34}

\dfrac {12-34}{34} = cos (\pi(t-1.25))

\dfrac {-22}{34} = cos(\pi(t-1.25))

2.27 = (\pi (t-1.25)

t = 2.72 seconds

Similarly, replacing cosine in the above equation with sine; we have:

\mathbf {y = 34 sin (\pi (t-1.25))+34}

\mathbf{12 = 34 sin ( \pi(t-1.25))+34}

\dfrac {12-34}{34} = sin (\pi(t-1.25))

\dfrac {-22}{34} = sin (\pi(t-1.25))

-0.703 = (\pi(t-1.25))

t = 2.527 seconds

Hence, the gum will reach 12 cm first at 2.527 sec and second time at 2.72 sec.

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