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krok68 [10]
3 years ago
12

10=1 bbb nbththhhhhhhhhhhhhhhhhhhhhhh

Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0

Answer:

Cool dude... very unique?

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There are 24 red flowers and 16 yellow flowers. What percent of the flowers are<br> yellow?
Taya2010 [7]
24+16=40
100/40=2.5
2.5 x 16 = 40
40% of the flowers are yellow

Hope this helps
8 0
3 years ago
How much would $200 invested at 6% interest compounded a 6% interest compounded annually be worth after 5 years, round to the ne
lidiya [134]
A= P(1 + r)^n  
where,
A= final balance 
P= initial quantity 
n= number of compounding periods 
r= percentage interest rate 
So,
P= $200 
n= 6 years 
r= 6%= 0.06 

=$200(1 + 0.06)^6 
<span>=$283.70</span>
7 0
4 years ago
Which of the following shows the graph of y = 2 l n x On a coordinate plane, a curve starts at (0, negative 2) in quadrant 4 and
enot [183]

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

Given:

f(x)= 2^{-x}=\frac{1}{2^x}

  • In the above choices it is clearly defined from the above equation that output rises in the first quadrant, the value of f(x) tends to be zero and increases into another second quadrant.
  • For x = 0, y, once again, has become 1, that is the function passes the y platform at (0,1).
  • Therefore an exponential function reaches y = 0 in quadrant 1 on a coordinate plane and rises into quadrant 2.
  • (0,1) stage is the temperature at which the y-axis intersects.
8 0
3 years ago
Read 2 more answers
suppose an investment of $8200 doubles in value every 7 years. how much is the investment worth after 28 years
kicyunya [14]
<span>Suppose an investment of $8200 doubles in value every 7 years. how much is the investment worth after 28 years

131,200</span>
3 0
3 years ago
Read 2 more answers
Mrs. Griffin wants to plant soybeans and corn on 100 acres of land. Soybeans require 6 hours of labor per acre, and corn require
Vlad [161]

9514 1404 393

Answer:

  • soybeans: 70 acres
  • corn: 30 acres

Step-by-step explanation:

Let x represent acres of soybeans. Then 100-x is the number of acres of corn. All of Mrs. Griffin's labor hours will be used when ...

  6x +8(100-x) = 660

  -2x +800 = 660 . . . . . simplify

  x -400 = -330 . . . . . . . divide by -2

  x = 70 . . . . . . . . . . . . . add 400

Mrs. Griffin should plant 70 acres of soybeans and 30 acres of corn.

_____

<em>Additional comment</em>

The problem is not well-specified, as there is no indication of the reason why Mrs Griffin should plant any number of acres of either crop. So, we assume the intent is to use all of the acres and labor hours available.

This makes the problem equivalent to a system of two equations in two variables. We effectively substituted (100-x) for the acres of corn, which might otherwise be its own variable.

Often, you're interested in maximizing or minimizing some objective function given these constraints. If we wanted to minimize labor, for example, we would plant all soybeans, since there is less labor involved. That would only require 600 hours of labor, instead of 660.

6 0
3 years ago
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