Answer:
The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of
.
Out of 100 people sampled, 42 had kids.
This means that
99% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).
Answer:
$7.7 million
Step-by-step explanation:
Given: $6.8 million profit made by company.
13% increase in profit every year.
Now, finding the company´s profit in the year of 2006.
As we know there is 13% increase in profit.
∴ Profit increase= 
Next adding company´s profit with increase in profit to get profit in the year 2006.
∴
≅ $7.7
The company´s profit in the year 2006 is $7.7 million.
Divide the number of fast balls by the total number of pitches:
240 / 384 = 0.625