Let's actually find the line of best fit...
m=(nΣyx-ΣyΣx)/(nΣx^2-ΣxΣx)
m=(11*836-130*55)/(11*385-3025)
m=2046/1210
m=93/55
b=(Σy-93Σx/55)/n
b=(55Σy-93Σx)/(55n)
b=(7150-5115)/(55*11)
b=185/55, so the line of best fit is:
y=(93x+185)/55
A) The approximate y-intercept (the value of y when x=0) is 185/55≈3.36.
Which means that those who do not practice at all will win about 3.36 times
B) y(13)=(93x+185)/55
y(13)≈25.34
So after 13 months of practice one would expect to win about 25.34 times.
So k=katie's' age
m=mara's age
k is 2 times as old as m
k=2m
sum is 24
add means sum
k+m=24
so we have
k+m=24 and
k=2m
subsitute
2m+m=24
add
3m=24
divide both sides by 3
m=8
subsitute again
k=2m
k=2(8)
k=16
katie=16
mara=8
Step-by-step explanation:
We have,
If a quadratic equation with real coefficients has a discriminant of -36.
The general form of quadratic equation is :
The discriminant of this equation is : 
If D=0, it will have 1 real roots
If D>0, it will have 2 real roots
If D<0, it will have no real roots
We have,
D = -36 < 0, so, the quadratic equation will have no real roots.
Answer:
After 4 years working for the company, he would make $79,000 of salary.
His salary after t years will be:
[te]S(t) = 69000 + 2500t[/tex]
Step-by-step explanation:
David just accepted a job at a new company where he will make an annual salary of $69000. David was told that for each year he stays with the company, he will be given a salary raise of $2500.
This means that after t years, his salary will be given by:
[te]S(t) = 69000 + 2500t[/tex]
How much would David make as a salary after 4 years working for the company?
[te]S(4) = 69000 + 2500*4 = 69000 + 10000 = 79000[/tex]
After 4 years working for the company, he would make $79,000 of salary.
